Answer:
v = 60 m/s
Explanation:
It is given that,
A wave is represented by the equation :
We need to find the velocity of the wave
The general equation of a wave is given by :
....(1)
Equation (1) can be written as :
...(2)
If we compare equation (1) and (2) we get :
The velocity of a wave is given by :
So, the velocity of the wave is 60 m/s.
Answer:
D = 43 m
Explanation:
given,
initial velocity = 18 m/s
angle θ = 60°
total horizontal distance covered by the shell is
applying conservation of momentum in horizontal direction
m v₀ cos θ = m₁v₁ + m₂ v₂
m v₀ cos θ = 0.5 m v₂
v₂ = 2 v₀ cos θ.
distance covered by the shell from point of explosion
R' = v t
=
=
=
= R
total distance traveled by the shell is
D =
= 1.5 R
=
D =
= 42.9 ≅ 43 m
D = 43 m
Answer:
u = 13.67 m/s
Explanation:
given,
window height = 2 m
window is 7.5 m off the ground on its path up
total distance from the ground to pass the window = 2 + 7.5 = 9.5 m
time taken to go past the window = 1.30 s
using equation of motion
u = 13.67 m/s
hence, the initial velocity of the ball is equal to 13.67 m/s
