The total resistance is 5.9.
The expected current is 1.
The current will be the lowest at point D.
Answer:
The change in momentum of the car is 16380.8 kg.m/s
Explanation:
Given;
mass of the car, m = 1600 kg
time of motion, t = 4.20s
force of friction on the car, F = 3900 N
final velocity of the car after the brakes were applied, v = 0
The initial velocity of the car during the motion is calculated as;
The change in momentum of the car is calculated as;
ΔP = mu
ΔP = 1600 x 10.238
ΔP = 16380.8 kg.m/s
Answer:
T = 8.19 s
, = 23 m / s
Explanation:
In the simple harmonic motion the equation that describes them is
y = A cos wt
Acceleration can be found by derivatives
a = d²y / dt²
v = dy / dt = - Aw sin wt
a= d²y / dt² = - A w² cos wt
For maximum acceleration cosWT = + -1
= -A w2
w = RA (/ A)
w = RA (1.8 9.8 / 30.0)
w = 0.767 rad / s
The angular velocity is related to the frequency
w = 2π f
f = 1 / T
w = 2π / T
T = 2π / w
T = 2π / 0.767
T = 8.19 s
For maximum speed the sin wt = + -1
= A w
= 30.0 0.767
= 23 m / s
Force = mass * acceleration = 1500kg * 8m/s²