Question

A ball is projected at an angle of elevation of 60 ° with an initial velocity of 120m/s.calculate

Answer 1

Explanation:

It is given that,

The angle of projection is 60 degrees

Initial velocity of the ball is 120 m/s

We need to find the time taken to get to the maximum height and the time of flight.

Time taken to reach the maximum height is given by :

$T=\dfrac{u^2\sin^2\theta}{2g}$

g is acceleration due to gravity

$T=\dfrac{(120)^2\times \sin^2(60)}{2\times 10}\\\\T=540\ s$

(ii) Time of flight,

$t=\dfrac{2u\sin\theta}{g}$

So,

$t=\dfrac{2\times 120\times \sin(60)}{10}\\\\t=20.78\ s$

Hence, this is the required solution.