Question

what is the velocity v2 of the liquid flowing out of the exit end of the pipe? assume the viscosity of the fluid is negligible and the fluid is incompressible. the acceleration of gravity is 9.8 m/s 2 and patm

Answer 1

The fluid is incompressible and has extremely little viscosity. Gravity accelerates at a rate of 9.8 m/s2 and follows a path that causes the liquid to go out of the pipe at a speed of 66.35 m/s.

What is the principle of Bernoulli?

Bernoulli's principle, which at first looks counterintuitive, describes the link between a fluid's speed and pressure. Bernoulli's principle states that locations in a horizontal flow of fluid will experience lower pressure than locations where the fluid is moving more slowly.

radius at initial end is given as = 0.24/2 = 0.12 m

now radius at end is given as = 0.05/2 = 0.025 m

utilizing the continuity equation:

A₁ V₁ = A₂ V₂

π (0.12)² × 2.88  = π (0.025)² × V₂

V₂ = 66.35 m/s

∴ The calculated exit terminal velocity is 66.35 m/s.

To know more about Bernoulli's principle, visit:

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