Answer:
60words/minute
Explanation:
If Sunitha can type 1800 words in half an hour, this can be expressed as;
1800 words = 30 minutes
To get her typing speed per minute, we will use the formula
Speed = Number of words/Time used
Typing speed = 1800/30
Typing speed = 60words/minute
Hence her typing speed in words per minute is 60words/minute
Vector 1 has components


and vector 2 has


Add these vectors to get the resultant, which has components


The magnitude of the resultant is

with direction
such that

or about 50º N of E.
The process of determining the value of the individual forces acting upon an object involve an application of Newton's second law (Fnet<span>=m. a) and an application of the meaning of the </span>net force<span>.</span>
Answer:
<em>A) 7.37 x 10^-4 N</em>
<em>B) The resultant force will be towards the -x axis</em>
Explanation:
The three masses have mass = 3500 kg
For the force of attraction between the mass at the origin and the mass -100 cm away:
distance r = 100 cm = 1 m
gravitational constant G= 6.67×10^−11 N⋅m^2/kg^2
Gravitational force of attraction
= 
where G is the gravitational constant
m is the mass of each of the masses
r is the distance apart = 1 m
substituting, we have
=
= 8.17 x 10^-4 N
For the force of attraction between the mass at the origin and the mass 320 cm away
distance r = 320 cm = 3.2 m
= 
substituting, we have
=
= 7.98 x 10^-5 N
Resultant force = (8.17 x 10^-4 N) - (7.98 x 10^-5 N) = <em>7.37 x 10^-4 N</em>
<em></em>
<em>B) The resultant force will be towards the -x axis</em>
Answer:
8018.2 N
Explanation:
Change in momentum, p is equivalent to force * time
M(vf-vi)=Ft where M represent mass of the car, vf is the final speed, vi is the intial speed of the car, F is the force in queation and t ia the time.
Since the car finally comes to rest then the final velocity ia zero. Substituting 1400 Kg for M, 0 for vf, 27 m/s for vi and 1.5 s for t then the first force is
1400(0-27)=1.5F
F=25200 N
Similarly, when we work with the same values but t changed to 2.2s
1400(0-27)=2.2 F
F2=17181.818181818 N
Reduced force will be 25200-17181.818181818=−8,018.181818182N
Approximately, 8018.2 N