Remain at rest.
Hope this helps you.
Answer:
a) The schematic illustrating is attached
b) The heat transfer to the heat engine is 2142.86 kJ, the heat transfer from the heat engine is 1392.86 kJ
c) The heat transfer to the heat engine is 1648.35 kJ, the heat transfer from the heat engine is 898.35 kJ
Explanation:
b) The heat transfer to the engine and the heat transfer from the engine to the air is:
Where
W = 750 kJ
n = 35% = 0.25
Replacing:
c) The efficiency of Carnot engine is:
The heat transfer to the heat engine is:
The heat transfer from the heat engine is:
Answer:
The actual work output is 1,125 kilojoules.
Explanation:
Energy efficiency is defined as the efficient use of energy. An appliance, process, or facility is energy efficient when it consumes less than the average amount of energy to perform an activity. Then, energy efficiency is the ratio between the amount of energy used in an activity and the amount expected to be carried out.
Efficiency is calculated as:
efficiency = output / input
Where output is the amount of mechanical work (in watts) or energy consumed by the process (in joules), and input (input) is the amount of work or energy that is used as input to carry out the process.
In this case:
- Efficiency always has a value between 0 and 1. In this case, efficiency=0.15
- output=?
- input= 7500 kilojoules
Replacing:
0.15=output/7500 kilojoules
Solving:
Output=0.15* 7500 kilojoules
output=1,125 kilojoules
<u><em>The actual work output is 1,125 kilojoules.</em></u>
I believe the answer is D, only a small part of it
Weak winds that blow for short periods of time with a short fetch.
