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Licemer1 [7]
2 years ago
11

Tonya’s dog-walking service charges a flat rate of $20 per month, plus $3 per mile that each dog is walked. Beth does not charge

a monthly fee for her dog-walking service, but she charges $5 per mile that each dog is walked. Write and solve an equation to find the number of miles m for which Tonya and Beth would charge the same amount.
Mathematics
1 answer:
vladimir1956 [14]2 years ago
4 0

Answer:

Ten miles

Step-by-step explanation:

Use this inequality

20 + 3m = 5m

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One hundred items are simultaneously put on a life test. Suppose the lifetimes
romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

7 0
3 years ago
A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee
Mariana [72]

Answer:

The questions and problem can be chosen in 1260 ways.

Step-by-step explanation:

Given that, a physics exam consists of 6 open-ended problem and  9 multiple choice questions.

The order of choosing does not matter.

So,we use combination to find ways.

The ways to choose  6 multiple choice from 9 is= ^9C_6

                                                                              =\frac{9!}{6!(9-6)!}

                                                                              =84

The ways to 2 open-ended question from 6  is= ^6C_2

                                                                              =\frac{6!}{2!(6-2)!}

                                                                             =15

Since pick 6 multiple choice out of 9 and 2 open-ended question out of 6 both are independent we have multiply both to find required ways.

Total number of ways is =(84×15)

                                        =1260.

6 0
3 years ago
What’s the difference need help
labwork [276]
You would circle the 5
4 0
2 years ago
Evaluate 3/5r +5/8swhen r =14 and s =8
Illusion [34]

Step-by-step explanation:

14×5=70

8×8=64

(3/70) + (5/64)

= (3×64)+(5×70)

----‐------------------

70×64

= (192+350)/448

=542/448

= 271/224

5 0
3 years ago
What’s 3/4s of 300 million
Blababa [14]
It’s 225,000,000= 225 million
4 0
3 years ago
Read 2 more answers
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