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horrorfan [7]
3 years ago
5

Did the test solution react with the supernatant from the test tube that had the largest amount of precipitate? what can you inf

er about the molar ratio of this reaction?
Chemistry
1 answer:
nydimaria [60]3 years ago
5 0

Answer: -

The test solution reacted with the supernatant from the test tube. In trial number 3 there was the largest amount of precipitate.

An amount of 0.019 g of precipitate was found. In trial 3, 3 mL CuSO₄ and 3 mL Na₂S was taken. Thus they were at a 1: 1 ratio.

From the fact that the most amount of precipitate was formed when the two reactants were at 1:1 ratio implies that at that ratio, all of the reactants reacted.

Thus the mole ratio of the reaction is 1 : 1.

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Consider the molecule 1-tert-butyl-3-methylcyclohexane. These two groups can be cis or trans. Which arrangement is more stable
Art [367]

Answer:

<u><em>Cis configuration is more stable</em></u>

Explanation:

Generally the is configuration of cycloalkenes is more thermo-chemically stable than the trans-configuration  double bonds, because the latter causes twists in the ring, resulting in higher strain.

This also mean that there is a greater force of repulsion between cis molecules (little r no twists).

I hope you find this explanation was clear and helpful.

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3 years ago
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Here they are:

Humidity

Air Temperature and Pressure

Wind Speed/Direction

Cloud Cover and what kind of clouds.

Also the amount of precipitation as well as what effects the different kind of weather phenomenon to change into e.g. Freezing rain, Hail, Straight Line winds, etc.  

6 0
3 years ago
Need help with question 1 &amp; 2
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For question 1:

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6 0
3 years ago
What do isotopes have in common
alexira [117]

Answer:

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6 0
4 years ago
Read 2 more answers
Calculate the number of moles of sodium carbonate originally present, if 6.0 ml of 0.100 M HCl were used to titrate the mixture
valina [46]

Answer:

0.0006 mole

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For HCl :

Molarity = 0.100 M

Volume = 6.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.0×10⁻³ L

Thus, moles of potassium iodide :

Moles=0.100 \times {6.0\times 10^{-3}}\ moles

Moles of HCl = 0.0006 moles

From the reaction shown below:-

HCl+Na_2CO_3\rightarrow NaHCO_3+NaCl

1 mole of HCl reacts with 1 mole of sodium carbonate.

So,

0.0006 mole of HCl reacts with 0.0006 mole of sodium carbonate.

<u>Moles of sodium carbonate = 0.0006 moles</u>

5 0
3 years ago
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