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Neko [114]
3 years ago
7

A chemist prepares a solution of magnesium fluoride MgF2 by measuring out 0.00598μmol of magnesium fluoride into a 50.mL volumet

ric flask and filling the flask to the mark with water. Calculate the concentration in /μmolL of the chemist's magnesium fluoride solution. Round your answer to 2 significant digits.
Chemistry
1 answer:
frutty [35]3 years ago
6 0

Answer:

0,12 μmol/L of MgF₂

Explanation:

Preparation of solutions is a common work in chemist's life.

In this porblem says that you measure 0,00598 μmol of MgF₂ in 50,0 mL of water and you must calculate concentration in  μmol/L

You have 0,00598 μmol but not Liters.

To obtain liters you sholud convert mL to L, knowing 1000mL are 1 L, thus:

50,0 mL (1L/1000mL) = 0,05 L of water.

Thus, concentration in  μmol/L is:

0,00598 μmol / 0,05 L = 0,12 μmol/L -The problem request answer with two significant digits-

I hope it helps!

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7. State the relationship between the concentration of ions and the boiling point for these solutions.
balu736 [363]

Answer:

  • 7. Linear relationship.

  • 8. Because ions carry charge that can move freely in solution.

  • 9. Solute: NaCl

            Solvent: H₂O

Explanation:

7. Elevation of the boling point.

The elevation of the boiling point of a solution respect to the pure solvent is a colligative property, meaning that it is proportional to the concentration of the solute particles.

        \Delta T_b=K_b\times i\times C

        T_b=T_b^0+K_b\times i\times C

Where, ΔTb is the elevation on the boiling point, Tb is the (elevated) boiling of the solution, point, Tb° is the boiling point of the pure solvent, i is the Van't Hoof factor, and C is the molal concentration (molality)

Thus the relation of the boiling point with the mola concentration (molality) is linear.

Using the table and some calculations, you can determine this relationship:

Trial  Mass of water   mass NaCl    moles NaCl     m             Tb

             kg                      g                   mol            mol/kg       ºC

  1        0.1                     8.76              0.15               1.5             101.5

 2        0.1                    17.52             0.30              3.0             103.1

 3        0.1                    20.28            0.45              4.5             104.6

 4        0.1                   35.04             0.60              6.0             106.1        

The number of moles for each trial were determinated dividing the mass in grams of the solute by the molar mass (58.44g/mol).

The molality concentrations (mole of solue per kg of solvent) were determined dividing the number of moles of each trial by the amount of solvent in kg.

As you see in the table, the column of Tb increases by an approximate constant value of 1.5ºC and the column of the molal concentration increases at a constant value of 0.15mol. Thus there is a constante rate of change of 1.5ºC/0.15mol = 10ºC/mol.

Since a constant rate of change means constant slope, this you conclude that the relationship is linear.

8. Ability to conduct an electric current.

Electric current is the flow of charges.

Ions are charged particles. There are positive ions (cations) and negative ions (ions) dissolved; this is, they are free to move in solution.

Current is the rate of flow of the charge, thus the greater the number of ions in solution, the greater the flow of charge, which is a greater current.

That explains why the greater the concentration of the ions in the solution the greater the abiity fo the solution to conduct electricity.

Pure water has a low concentration of ions (H⁺ and OH⁻) thus it has a very low ability to conduct electricity. But adding a solute, like an acid, a base, or a salt (like NaCl in this case), increases the number of ions in solution, and thus a solution with a high concetration of solute will have a great ability to conduct electricity.

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  • The <em>solvent</em> is the component of the solution that is present in greater amount and is able to dissolve the solute. In this case the solvent is water, H₂O.

The concentrations of the solute normally are relatively low, because they are the component with less particles in the solution.

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