This is the case because in a fission reaction you are essentially having a particle or neutron split apart and or interact with an unstable nuclei, causing smaller nuclei to form upon the collision, which would most likely cause a chain reaction to occur, since a great deal of energy is involved in breaking apart the nuclei, more energy would be released if this is done, compared to electrons being transferred to form chemical bonds, or causing electrons to be dislodged from a chemical covalent bond.
Explanation:
Structural Formulas v. Empirical Formulas
An empirical formula (like a molecular formula) lacks any structural information about the positioning or bonding of atoms in a molecule. It can therefore describe a number of different structures, or isomers, with varying physical properties. For butane and isobutane, the empirical formula for both molecules is C2H5, and they share the same molecular formula, C4H10. However, one structural representation for butane is CH3CH2CH2CH3, while isobutane can be described using the structural formula (CH3)3CH.
<u>Answer:</u> The molar concentration of ethylenediminediacetic-dihydrate and sodium ions in solution is 0.1976 M and 0.3952 M respectively.
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
![\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}](https://tex.z-dn.net/?f=%5Ctext%7BMolarity%20of%20the%20solution%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20solute%7D%7D%7B%5Ctext%7BMolar%20mass%20of%20solute%7D%5Ctimes%20%5Ctext%7BVolume%20of%20solution%20%28in%20L%29%7D%7D)
We are given:
Mass of solute (disodium ethylenediaminetetraacetic acid dihydate) = 36.7845 g
Molar mass of disodium ethylenediaminetetraacetic acid dihydate = 372.24 g/mol
Volume of solution = 0.5000 L
Putting values in above equation, we get:
![\text{Molarity of solution}=\frac{36.7845g}{372.24g/mol\times 0.5000L}\\\\\text{Molarity of solution}=0.1976M](https://tex.z-dn.net/?f=%5Ctext%7BMolarity%20of%20solution%7D%3D%5Cfrac%7B36.7845g%7D%7B372.24g%2Fmol%5Ctimes%200.5000L%7D%5C%5C%5C%5C%5Ctext%7BMolarity%20of%20solution%7D%3D0.1976M)
As, 1 mole of disodium ethylenediaminetetraacetic acid dihydate produces 2 moles of sodium ion and 1 mole of ethylenediminediacetic-dihydrate.
Concentration of ethylenediminediacetic-dihydrate in solution = ![(1\times 0.1976)=0.1976M](https://tex.z-dn.net/?f=%281%5Ctimes%200.1976%29%3D0.1976M)
Concentration of sodium ions in solution = ![(2\times 0.1976)=0.3952M](https://tex.z-dn.net/?f=%282%5Ctimes%200.1976%29%3D0.3952M)
Hence, the molar concentration of ethylenediminediacetic-dihydrate and sodium ions in solution is 0.1976 M and 0.3952 M respectively.
The chemical formula tells us the mole ratio. CO2 = 1 CO2 molecule : 1 C atom : 2 O atoms. 1 C12H22O11 molecule: 12 O2 molecules : 12 CO2 molecules : 11 H2O molecules.
Answer:
5.59x10^-3 moles
Explanation:
The balanced equation for the reaction is given below:
HCl + KOH —> KCl + H2O
Now we can obtain the number of mole of HCl required to produce 5.59x10^-3 moles of KCl as follow:
From the balanced equation above, 1 mole of HCl produced 1 mole of KCl.
Therefore, 5.59x10^-3 moles of HCl will also produce 5.59x10^-3 moles of KCl.
From the illustration made above, we can see evidently that 5.59x10^-3 moles of HCl is required to produce 5.59x10^-3 moles of KCl