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sveta [45]
3 years ago
12

Oxidation and reduction reactions (redox) involve the loss and gain of electrons. Half-reactions are a way for us to keep track

of how many electrons are gained or lost by a particular species during a chemical reaction. These half reactions can be useful in understanding how batteries work, and how other reactions that occur in your body and in nature work as well. Questions 1. In the model, are electrons lost or gained during oxidation
Chemistry
1 answer:
jok3333 [9.3K]3 years ago
4 0

Answer:

Electrons are lost during oxidation (LEO)

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The intermolecular forces present in CH 3NH 2 include which of the following? I. dipole-dipole II. ion-dipole III. dispersion IV
astra-53 [7]

Answer:

I. dipole-dipole

III. dispersion

IV. hydrogen bonding

Explanation:

Intermolecular forces are weak attraction force joining nonpolar and polar molecules together.

London Dispersion Forces are weak attraction force joining non-polar and polar molecules together. e.g O₂, H₂,N₂,Cl₂ and noble gases. The attractions here can be attributed to the fact that a non -polar molecule sometimes becomes polar because the constant motion of its electrons may lead to an uneven charge distribution at an instant.

Dispersion forces are the weakest of all electrical forces that act between atoms and molecules. The force is responsible for liquefaction or solidification of non-polar substances such as noble gas an halogen at low temperatures.

Dipole-Dipole Attractions are forces of attraction existing between polar molecules ( unsymmetrical molecules) i.e molecules that have permanent dipoles such as HCl, CH3NH2 . Such molecules line up such that the positive pole of one molecule attracts the negative pole of another.

Dipole - Dipole attractions are more stronger than the London dispersion forces but weaker than the attraction between full charges carried by ions in ionic crystal lattice.

Hydrogen Bonding is a dipole-dipole intermolecular attraction which occurs when hydrogen is covalently bonded to highly electronegative elements such as nitrogen, oxygen or fluorine. The highly electronegative elements have very strong affinity for electrons. Hence, they attracts the shared pair of electrons in the covalent bonds towards themselves, leaving a partial positive charge on the hydrogen atom and a partial negative charge on the electronegative atom ( nitrogen in the case of CH3NH2 ) . This attractive force is know as hydrogen bonding.

7 0
3 years ago
Most living things need oxygen to survive. These two body systems bring oxygen into your body and then move to all your body par
Murljashka [212]
Your answer would be D. As the circulatory system pumps oxygen rich blood through the body, and the respiratory system helps you to breath. Hope this helps!
7 0
3 years ago
Read 2 more answers
How many moles of glucose (C6H12O6) are in 5.0 liters of a 2.5 M C6H12O6 solution?
zhannawk [14.2K]
N = M x V      

n = 2.5 x 5.0
 
n = 12.5 moles of C6H12O6
5 0
3 years ago
What is the hybridization of the central atom, electron geometry, and molecular geometry of H3CCCH?
DIA [1.3K]

Answer:

Hybridization: sp

Electron geometry: linear

Molecular geometry: linear

Explanation:

H₃CCCH can also be written as its Lewis structure which is shown in the figure attached. The figure shows that the central carbon atom makes a single bond with CH₃ and a triple bond with CH. This means that the hybridization of the carbon is sp and both the electron and molecular geometry are linear with an 180° bond angle.

6 0
4 years ago
The center on your school’s basketball team is 6 ft 10 in tall. How tall is the player in millimeters (mm)?
svp [43]

The answer is 6 ft 10 inches in millimeters (mm) is 0.833 ft.

Given,

The center of the school's basketball team is 6 ft 10 inches tall.

We have to convert the height of the player from feet and inches to feet.

Using the conversion factor,

1 ft = 12 inches

or, 12inches/ 1 ft

Converting 6ft 10 inches to ft, we get;

10 inches × 1 ft/ 12inches

= 0.833 ft

Therefore 6 ft 10 inches in millimeters (mm) is 0.833 ft.

Unit conversion is a method in which we multiply or divide with a particular numerical factor and then finally round off to the nearest significant digits.

To learn more about Millimeter and Unit conversions, visit: brainly.com/question/26371870

#SPJ4

5 0
2 years ago
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