Write an equation in slope-intercept form (0,4) and (4,2) PLEASE HELP, DUE TMR
1 answer:
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The slope of the line parallel to the line –x + 3y = 6 is a 1/3 option (A) 1/3 is correct.
<h3>What is the slope?</h3>The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).
It is given that:
The equation of the line:
–x + 3y = 6
Write the equation in standard form:
y = x/3 + 6/3
y = x/3 + 2
m = 1/3
The slope of the line parallel to the line –x + 3y = 6
M = 1/3
Thus, the slope of the line parallel to the line –x + 3y = 6 is a 1/3 option (A) 1/3 is correct.
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The equation for the line passing through point A and perpendicular to AB will be y-0.5x=6, the gradient of line AB is -2, and the gradient of a line perpendicular to AB is 0.5.
<h3 /><h3>What is the slope or gradient?</h3>A numerical assessment of a line's angle relative to the ground is known as the slope.
Given data;
m₁ is the slope of line AB
m₂ is the slope of a line perpendicular to AB
The coordinate points are,
A,(x₁,y₁)= (0, 6)
B,(x₂,y₂)=(3, 0).
The gradient of line AB;
The slope of the lines has a perpendicular relation is -1;
m₁ × m₂ = -1
(-2) × m₂ = -1
m₂ = 1/2
m₂ = 0.5
The equation of the line passing through point A and perpendicular to AB;
(y - y₁) = m₂(x-x₁)
(y-6)=0.5(x-0)
y-6 = 0.5 x
y-0.5x=6
Hence, the gradient of line AB, the gradient of a line perpendicular to AB, and the equation of the line passing through point A and perpendicular to AB will be -2,0.5 and y-0.5x=6.
To learn more about the slope, refer to the link;
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