All categories

3 years ago

Given the figure below, find the values of x and z.

Mathematics

1 answer:

stepan [7]3 years ago

4 0

Answer:

z = 96; x = 8.

Step-by-step explanation:

z = 96. This is because the angle measuring z degrees is a vertical angle of the angle measuring 96 degrees, which means that the two angles are congruent.

The angle measuring 5x + 44 degrees forms a straight angle with the 96 degree angle. That means that the measurements of the two angles will add to be 180 degrees.

5x + 44 + 96 = 180

5x + 140 = 180

5x = 40

x = 8

Hope this helps!

You might be interested in

Help me if u can and thank you :)

DanielleElmas [232]

Answer:

320km = 12L

296 km = xL

x = (296 × 12)/320

x = 11.1 liters

3 0

3 years ago

Read 2 more answers

10 POINTS. I WILL MARK BRAINLIEST

defon

1. BC = 9 tan 45 = 9 ft
AC = 9 tan 60 = 9 sqrt(3) ft
AB = AC - BC = 9sqrt3 - 9 ft ~ 6.59 ft

2. G-Zoo = 200sqrt3 / tan 60 = 200 ft
G-Library = 200sqrt3 / tan 30 = 600 ft
Zoo-Library = G-Library - G-Zoo = 600 - 200 = 400 ft

7 0

3 years ago

Read 2 more answers

Find (f o g)(2) and (f+g)(2) when f(x)=1/x and g(x)=4x+9

Pavel [41]

I believe the answers are:
(f o g) (2)= 1/17 and (f+g) (2)= 17.5

7 0

3 years ago

Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic t.

lawyer [7]

Using the t-distribution, it is found that the p-value of the test is 0.007.

At the null hypothesis, it is tested if the mean lifetime is not greater than 220,000 miles, that is:

$H_0: \mu \leq 220000$

At the alternative hypothesis, it is tested if the mean lifetime is greater than 220,000 miles, that is:

$H_1: \mu > 220000$ .

We have the standard deviation for the sample, thus, the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem:

$\overline{x} = 226450, \mu = 220000, s = 11500, n = 23$

Then, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{226450 - 220000}{\frac{11500}{\sqrt{23}}}$

$t = 2.69$

We have a right-tailed test(test if the mean is greater than a value), with t = 2.69 and 23 - 1 = 22 df.

Using a t-distribution calculator, the p-value of the test is of 0.007.

A similar problem is given at brainly.com/question/13873630

8 0

2 years ago

What is the lower extreme and the upper extreme of the numbers 45, 51, 53, 55, 55, 65, 75, 81, 84, 87, 93, 93, 95, 96, 100

Greeley [361]

The lower extreme is the least value in the data set and the upper extreme is the greatest value. These two values can therefore be found directly from an ordered set of data.
Lower extreme is 45
Upper extreme is 100
Good luck

7 0

3 years ago