In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
Answer:
-2 ≤ f(x) ≤ 4
Step-by-step explanation:
The range is the set or group of all the y-coordinates of the function. This means it has all the values from the bottom point at -2 to the top point at 4. It is written as an inequality.
-2 ≤ f(x) ≤ 4
Correct answer is 4:13 am
Answer:b and c
Step-by-step explanation:
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