All categories

4 years ago

Can anyone pls help me in dis pls

Mathematics

1 answer:

Brut [27]4 years ago

8 0

(a + b)² and c² + 4(1/2 ab) both represent the area of the outer square and are equal.

Step-by-step explanation:

Step 1: The below reasons explain why the expression is a true equation.

1. The left hand side expression (a + b)² finds the area of the outer square by squaring its side length.

[In the figure, side length of the outer square = a + b and area of a square = (side length)²]

2. The right hand side expression c² + 4(1/2 ab) finds the area of the outer square by adding the area of the inner square and the four triangles.

[In the figure the length of the inner square is c, the triangles have a base a and height b and area of a triangle = 1/2 base × height]

So the left hand side and right hand side of the expression is equal.

You might be interested in

B. Complete the diagram to find the unit rate for the 5-class block.What is the cost per class?

Assoli18 [71]

Answer:

There is no picture

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

105,159 rounded to the nearest ten thousand

Dima020 [189]

105,159 rounded to the nearest ten thousand is 100,000

8 0

3 years ago

Read 2 more answers

What number can be use in the blank to make the equation true?<br><br> 3x + 1 = 3x +___

MAXImum [283]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy

Alborosie

Answer:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

$df = n-1=75-1 =74$

The p value is:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

$\bar X = 3.13 , s =0.03 , n =75$

The statistic to check the hypothesis is given by:

$t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

Replacing the info given we got:

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

The degrees of freedom are given by:

$df = n-1=75-1 =74$

The p value since is a right tailed ted is given by:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

6 0

3 years ago

5/6 x 3/20 as a fraction

Fantom [35]

Answer:

1/8

Step-by-step explanation:

7 0

3 years ago