All categories

3 years ago

Need some assistance

Mathematics

1 answer:

Olenka [21]3 years ago

4 0

Answer: Choice A

y - 35 = 7(x + 15)

=========================================

Explanation:

Pick any two columns to find the slope. I'll pick the first two columns

(x1,y1) = (-40, -140) and (x2,y2) = (-30, -70)

m = (y2 - y1)/(x2 - x1)

m = (-70 - (-140))/(-30 - (-40))

m = (-70 + 140)/(-30 + 40)

m = 70/10

m = 7

This narrows our choices between A and B

Now if we used (x1,y1) = (-40, -140) in the point slope formula, then we wouldn't get either A or B. But luckily we can use any point from the table in place of this. It turns out we'll use the third column to get (x1,y1) = (-15,35). Use trial and error.

So,

y - y1 = m(x - x1)

y - 35 = 7(x - (-15))

y - 35 = 7(x + 15)

You might be interested in

A rectangular book measure 12*15. What is the length of its diagonal?

schepotkina [342]

Answer:

19.21

Step-by-step explanation:

use the formula

$\sqrt{w^{2}+l^{2} }$

and simplify

$\sqrt{12^{2}+15^{2} }$

$\sqrt{144+225}$

$\sqrt{369}$ = 19.21

3 0

3 years ago

What is the first quartile of the following data set

krok68 [10]

Answer:

The first quartile, Q1, is the median of {3, 5, 7, 8}. Since there is an even number of values, we need the mean of the middle two values to find the first quartile: .

Step-by-step explanation:

Example 1: Find the first and third quartiles of the set {3, 7, 8, 5, 12, 14, 21, 15, 18, 14}

8 0

3 years ago

What is the excluded value? y2-y+5/y+4

WITCHER [35]

The given term is: $\frac{ y^{2}-y+5 }{y+4}$

Since here, the numerator i.e. $y^{2}-y+5$ cannot be factorized.

SO, the only excluded value is found on the basis of the denominator. The denominator should not be equal to 0, otherwise, the fraction will turn out to be zero.
SO, if y $\neq$ -4, then denominator will not be zero.
Therefore, the excluded value is -4

5 0

3 years ago

Read 2 more answers

there are 8 students on the minibus. five of the students are boys. what fraction of the students are boy

meriva

Students on the minibus = 8
students that are boys = 5
fraction of the student that are boys = ?
we can write fraction as the numerator and denominator so here the fraction of boys students is = 5/8
this fraction means and shows that there are 5 students are boys from 8 students.

3 0

4 years ago

Five companies (A, B, C, D, and E) that make elec- trical relays compete each year to be the sole sup- plier of relays to a majo

NNADVOKAT [17]

Answer:

$P(a | e') = 0.22$

$P(b | e') = 0.28$

$P(c | e') = 0.33$

$P(a | e' , d' , b') = 0.57$

Step-by-step explanation:

From the question we are told that

The probabilities are

Supplier chosen A B C

Probability P(a) = 0.20 P(b) = 0.25 P(c) = 0.15

D E

P(d) = 0.30 P(e) = 0.10

Generally the new probability of companies A being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(a | e') = \frac{P (a \ and \ e')}{P(e')}$

$P(a | e') = \frac{P (a)}{P(e')}$

$P(a | e') = \frac{P (a)}{1- P(e)}$

=> $P(a | e') = \frac{ 0.20}{1- 0.10}$

=> $P(a | e') = 0.22$

Generally the new probability of companies B being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(b | e') = \frac{P (b \ and \ e')}{P(e')}$

$P(b | e') = \frac{P (b)}{P(e')}$

$P(b | e') = \frac{P (b)}{1- P(e)}$

=> $P(b | e') = \frac{ 0.25}{1- 0.10}$

=> $P(b | e') = 0.28$

Generally the new probability of companies C being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(c | e') = \frac{P (c \ and \ e')}{P(e')}$

$P(c | e') = \frac{P (c)}{P(e')}$

$P(c | e') = \frac{P (c)}{1- P(e)}$

=> $P(c | e') = \frac{ 0.15}{1- 0.10}$

=> $P(c | e') = 0.17$

Generally the new probability of companies D being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(d | e') = \frac{P (d \ and \ e')}{P(e')}$