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3 years ago

For what value of x is the equation 8x-2(x-7)=20 true?

Mathematics

1 answer:

sukhopar [10]3 years ago

6 0

Answer:

x = 1

Step-by-step explanation:

Given

8x - 2(x - 7) = 20 ← distribute parenthesis on left side

8x - 2x + 14 = 20, that is

6x + 14 = 20 ( subtract 14 from both sides )

6x = 6 ( divide both sides by 6 )

x = 1

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in a canoe race, a team paddles downstream 480 m in 60 s. The same team makes the trip upstream in 80 s. Find the team's rate in

Vera_Pavlovna [14]

480=60(v+s)

480=60v+60s

8=v+s

s=8-v...

480=80(v-s) using s from above we get:

480=80(v-(8-v))

6=v-8+v

6=2v-8

2v=14

v=7, and since s=8-v, s=1

So the rate of the team is 7m/s while the rate of the stream is 1m/s

7 0

3 years ago

The expression 20l + 25g - 10 gives the number of dollars that Josie makes from mowing lawns and raking gardens.

vodka [1.7K]

20l + 25g -10
replace G with 4 and L with 3

20(3) + 25(4) - 10

60 + 100 - 10

160 - 10

150

he made $150

4 0

3 years ago

Need help please help

lilavasa [31]

Answer:

27 of the pets are dogs.

Step-by-step explanation:

Real easy way to do this, treat 45 (the total) as 100. So, do 45/100 then multiply the result of that by 60, and you end up with 27.

45/100=0.45

0.45*60=27

7 0

3 years ago

Use the power series for 1 1−x to find a power series representation of f(x) = ln(1−x). What is the radius of convergence? (Note

Viktor [21]

a. Recall that

$\displaystyle\int\frac{\mathrm dx}{1-x}=-\ln|1-x|+C$

For $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n$

By integrating both sides, we get

$\displaystyle-\ln(1-x)=C+\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}$

If $x=0$ , then

$\displaystyle-\ln1=C+\sum_{n=0}^\infty\frac{0^{n+1}}{n+1}\implies 0=C+0\implies C=0$

so that

$\displaystyle\ln(1-x)=-\sum_{n=0}^\infty\frac{x^{n+1}}{n+1}$

We can shift the index to simplify the sum slightly.

$\displaystyle\ln(1-x)=-\sum_{n=1}^\infty\frac{x^n}n$

b. The power series for $x\ln(1-x)$ can be obtained simply by multiplying both sides of the series above by $x$ .

$\displaystyle x\ln(1-x)=-\sum_{n=1}^\infty\frac{x^{n+1}}n$

c. We have

$\ln2=-\dfrac\ln12=-\ln\left(1-\dfrac12\right)$

$\displaystyle\implies\ln2=\sum_{n=1}^\infty\frac1{n2^n}$

4 0

3 years ago

What is the length of this rectangle?

solong [7]

Answer:

long

Step-by-step explanation:

well, as you can clearly see this is certainly not a short rectangle. maybe a little stocky, but certainly not short. also, I'm not very good at math, so dont ask me.

6 0

3 years ago

Read 2 more answers