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Anni [7]
3 years ago
13

On an 88 question test, LeeBeth missed 11 questions. What is her exact grade for that test?

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
8 0
100/88 = 1.13 1.13*11= 12.43 100-12.43= 87.53 So around 87-88
guapka [62]3 years ago
3 0
Lee Beth missed 11 questions = 88-11=77
She got 77 out of 88 questions or 77/88 = 87.5%
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This question is confusing. Please help me!
patriot [66]

Answer:

C. 490.

Step-by-step explanation:

25% = 0.25.

If the number of emails that Ryan and Taylor each received  is x emails then Sara received  2x + 0.25 * 2x = 2.5 emails.

So 2x + 2.5x = 882

x = 882/4.5

x = 196.

So Sara received 2.5 * 196

= 490 emails.

5 0
3 years ago
Let f(x)=x2−3x−4 . What is the average rate of change from x = 7 to x = 10? Question 6 options: 24 14 66 42
Fed [463]
Just find the slope between the points

basically find (f(10)-f(7))/(10-7)

f(7)=7^2-3(7)-4=49-21-4=24
f(10)=10^2-3(10)-4=100-30-4=66

slope=(66-24)/(10-7)=42/3=14
average rate of change is 14
8 0
3 years ago
What is 5.5 converted to miles?
Otrada [13]

Answer: 3.42 miles

Step-by-step explanation:

5.5 cm converts to 3.41754e-5 miles

5 0
2 years ago
Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos
Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$ P_{1} = (- 1, 4) $

$ P_{2} = (6, 2) $    and

$ P_{3} = (4, - 5) $

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $ (x_1, y_1) $ and $ (x_2, y_2) $ is:

                                 $ \sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+}   \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}} $

Length between $ P_1 $ and $ P_{2} $ , (Side 1) :

$ (x_1, y_1) = (- 1, 4) $     and

$ (x_2, y_2) = (6, 2) $

Distance = $ \sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2 $

$ = \sqrt{7^2 + 2^2} $

$ = \sqrt{49 + 4} $

$ = \sqrt{\textbf{53}} $

Length of Side 1 = $  \sqrt{\textbf{53}} $ units.

Distance between $ P_1 $ and P_2 , (Side 2):

$ (x_1, y_1) = (-1, 4) $

$ (x_2, y_2) = (4, - 5) $

Distance = $ \sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2 $

$ = \sqrt{ 25 + 81 } $

$ = \sqrt{\textbf{106}} $

Length of Side 2 = $ \sqrt{\textbf{106}} $ units.

Distance between $ P_2 $ and $ P_3 $ , Side 3 :

$ (x_1, y_1) = (4, 5) $

$ (x_2, y_2) = (6, 2) $

Distance = $ \sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2} $

$ = \sqrt{49 + 4} $

$ = \sqrt{\textbf{53} $

Length of Side 3  = $ \sqrt{\textbf{53}} $ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$ \bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2 $

i.e, 53 + 53  = 106

Hence, the triangle is a right - angled triangle as well.

7 0
3 years ago
please answer this with an explanation since my homework requires it thanks and I really appreciate it
cricket20 [7]

Answer:

<h2>D. 10</h2>

Step-by-step explanation:

There are 5 students in each scenario, so we just add 5 and 5 together. The answer is 10.

I'm always happy to help :)

8 0
2 years ago
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