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Afina-wow [57]
3 years ago
9

What is one tenth of 200?

Mathematics
1 answer:
jekas [21]3 years ago
6 0
20 is one tenth of 200
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Question 1
Scrat [10]

Answer:

17.11 meters

Step-by-step explanation:

You are using trigonometry in this problem.

The height of the flagpole represents the side <u><em>opposite</em></u> the given angle.

The base of the triangle is given as 19 meters and represents the side <u><em>adjacent</em></u> to the given angle.

Out of the main trigonomentric functions (sine, cosine, and tangent), only tangent uses both the opposite and adjacent sides.

Tan(angle) = opposite / adjacent

If we plug in what we know into that equation: <em>tan(42 degrees) = h / 19</em>

This means that <em>your answer = 19 * tan(42) = 17.11</em> meters

6 0
3 years ago
Consider the equation below.
Marta_Voda [28]
Be because I did this it’s just extremely hard to explain how to trust OK open helps
7 0
3 years ago
What is the hafe way number between 12 and 34 i need this anwer asap
timama [110]
23 is the middle number from 12 to 34.
6 0
4 years ago
Xy - 11 = 5 show the direct variation expalin your reasoning
Vedmedyk [2.9K]
Hey there, Lets solve this one by one 

Firstly, a<span>dd </span>11<span> to both sides 

</span>xy=5+11 
<span>
Now, </span><span>Simplify </span><span>5+11</span><span> to </span><span>16 

</span>xy=16 
<span>
Finally, d</span><span>ivide both sides by variable </span><span>y 

</span>x = 16 /y<span>
</span>
5 0
3 years ago
A manufacturing process is designed to produce bolts with a 0.25-in. diameter. Once each day, a random sample of 36 bolts is sel
Troyanec [42]

Answer:

0.6170

Step-by-step explanation:

Given that a manufacturing process is designed to produce bolts with a 0.25-in. diameter.

i.e. no of bolts which are produced as per standard is X means then

X is normal with mean = 0.250 and std dev = 0.04

No of bolts tested = 36

If this mean falls outside the interval (0.230,0.270) the production would be shut down.

i.e. P(|x-25|>0.20) =production shut down probability

P(|x-25|>0.20)\\=P(|Z|>0.5)\\=2(0.5-0.1915)\\= 0.6170

3 0
3 years ago
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