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3 years ago

Please help I will reward brainliest

Mathematics

2 answers:

Tresset [83]3 years ago

8 0

Answer:

DEH and HEJ are complementary angles for example.

Step-by-step explanation:

We need to provide any 2 angles that sum to 90deg. We can clearly see that DEH and HEJ are complementary, we can see the same for JEK and KEF.

I don't believe there's more.

gulaghasi [49]3 years ago

8 0

2 x 3= 6. 6-6=0 What that guy said ^

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Can someone help with this?

sammy [17]

Just go to were the line intercepts the y axis so -2 and rise over run so 2 up and 2 over but its negative so C should be correct.

6 0

2 years ago

Read 2 more answers

How much of the backyard is NOT being used for a vegetable garden or pet exercise area?

Nimfa-mama [501]

Area of backyard is not being used 7792 square feet.

Solution:

Length of the backyard = 181 ft

Width of the backyard = 48 ft

Area of the backyard = length × width

= 181 × 48

Area of the backyard = 8688 square feet

Base of the triangle = 16 ft

Height of the triangle = 28 ft

Area of the triangle = $\frac{1}{2}\times \text{base}\times \text{height}$

$$=\frac{1}{2}\times {16}\times {28}$

Area of the triangle = 224 square feet

Length of the rectangle = 32 ft

Width of the rectangle = 21 ft

Area of the rectangular vegetable garden = length × width

= 32 × 21

Area of the rectangular vegetable garden = 672 square feet

Area of backyard not used

= Area of backyard – Area of the triangle + Area of the rectangle

= 8688 – 224 – 672

= 7792 square feet

Area of backyard is not being used 7792 square feet.

3 0

4 years ago

Identify all solutions for a triangle with A - 38°, b= 10, and a=8. Round to the nearest tenth.

Alex

Answer:

B= 50.35°

C=91.65°

c= 12.77

Step-by-step explanation:

Given:

A = 38°

b= 10 and a=8.

Required:

angles B and C, and sides c.

By using the rule for law of sines

$sin B=b\frac{sinA}{a} = \frac{(10)(0.62)}{8}$ => 0.77

B= $sin^-^1$ (0.77) => 50.35°

For angle C:

angle C= 180 - A - B => 180 - 38 - 50.35

=91.65°

For side c:

c= $a(\frac{sinC}{sinA} )$ => 8( $\frac{0.99}{0.62}$ )

c= 12.77

3 0

3 years ago

Read 2 more answers

Serjik [45]

$\qquad$ $\purple{\twoheadrightarrow\bf 2cos^2A = 1 + cos2A }$

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$\qquad$ $\purple{\twoheadrightarrow\bf 2 sinA cosA = sin2A}$

________________________________________

$\qquad$ $\twoheadrightarrow\bf L.H.S$

$\qquad$ $\pink{\twoheadrightarrow\bf cos^4 x}$

$\qquad$ $\twoheadrightarrow\sf \dfrac{1}{4} (2cos^2x)^2$

$\qquad$ $\twoheadrightarrow\sf \dfrac{1}{4}(1+cos2x)^2$

$\qquad$ $\twoheadrightarrow\sf \dfrac{1}{4}(1+2cos2x+cos^22x)$

$\qquad$ $\twoheadrightarrow\sf \dfrac{1}{4}+\dfrac{1}{2}cos2x+\dfrac{1}{8}\times 2cos^22x$

$\qquad$ $\twoheadrightarrow\sf \dfrac{1}{4}+\dfrac{1}{2}cos2x+\dfrac{1}{8}\times(1+cos4x)$

$\qquad$ $\pink{\twoheadrightarrow\bf \dfrac{1}{4}+\dfrac{1}{2}cos2x+\dfrac{1}{8}\times cos4x}$

$\qquad$ $\twoheadrightarrow\bf R.H.S$

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$\qquad$ $\pink{\twoheadrightarrow\bf cos^6\theta +sin^6\theta }$

$\qquad$ $\twoheadrightarrow\sf (cos^2\theta)^3 +(sin^2\theta)^3$

$\twoheadrightarrow\sf (cos^2\theta +sin^2\theta)^3 -3cos^2\theta sin^2\theta (cos^2\theta +sin^2\theta)$

$\qquad$ $\twoheadrightarrow\sf 1-3\times \dfrac{1}{4}\times 4(sin\theta cos\theta) ^2$

$\qquad$ $\twoheadrightarrow\sf 1-\dfrac{3}{4}(2sin\theta cos\theta) ^2$

$\qquad$ $\pink{\twoheadrightarrow\sf 1-\dfrac{3}{4}sin^22\theta}$

$\qquad$ $\twoheadrightarrow\bf R.H.S$

3 0

3 years ago

30 points,<br> please solve for x asap<br><br> -2/3(4x-2) = 3x+7

11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

77777777777 and then you multiply

3 0

3 years ago