The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
#SPJ4
Answer:The accompanying table shows the number of trials and the ... Write the exponential regression equation for this set of data, rounding all values to no decimal places. Using this equation, find the value of her stock, to the nearest dollar, 10 years ... culture over a 5-hour period, where x is the time, in hours, and y is the number.
mark me brinlest plzz
Step-by-step explanation:
1 cubic foot has 7.48 gallons of water.
Volume of water tank = 234 cubic feet
So, the number of gallons are = 
Hence, the water tank can hold 1750.32 gallons of water.
Answer:
$65.35
Step-by-step explanation:
- First you have to divide 5.4% by 100
- Take 5.4/100 and multiply it by 62
- Take the number you get from step 2 and add it to 62! (:
5w^2 = A
You would multiply the width (w) by 5 because it's 5 times more than twice it's width. Then w (Width) would be to the power of 2 because it's 5 times more than twice its width. And this will all equal the Area (a)
