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Delicious77 [7]
3 years ago
11

If you are traveling at a speed of 50 miles per hour, how many feet per second is this?

Mathematics
1 answer:
Andrews [41]3 years ago
5 0

A handy conversion to remember is that 60 mph equals 88 feet per second.

Therefore, 50 mph will be (5/6) of 88 feet per second or 73.3333333333 feet per second.



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Which ordered pair would form a proportional relationship with the point graphed below?
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Answer:

(90,60)

Step-by-step explanation:

if you look closely through the linear graph, the line crosses through (90,60) and not the other given pairs.

  • proportional relationships are plots that also match in the same graphing format (keep in mind when you have trouble next time)
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What is 463,462 rounded to the nearest ten?
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Answer: 460,000

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What is the value of x?
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x^2=40^2+9^2\\x^2=1600+81\\x^2=1681\\x=\sqrt{1681}=41

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How do you solve this??? I need it fast please help with steps.<br> (x+3)(x+1)^2(x−4)&gt;0
scZoUnD [109]

Answer:

  x < -3 or x > 4

Step-by-step explanation:

The product of the factors is 4th-degree, and the leading coefficient is 1 (positive).

The factors tell you the following about the zeros:

  x = -3 . . . sign change from + to -

  x = -1 . . . graph touches, but no sign change. - on either side of x=-1

  x = 4 . . . sign change from - to +

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The function will be positive for x < -3 and for x > +4.

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<em>Additional comments</em>

The value of the function is zero when any of its factors is zero. The value of a factor changes sign when the value of x changes from one side of the 0 to the other. For example, here, we have x+1 as a factor, so x=-1 is a zero. When x = -0.9, the factor is positive (-0.9 +1 = 0.1). When x = -1.1, the factor is negative (-1.1 +1 = -0.1). If this factor were to the first power, it would cause the value of the function to change sign at x=-1.

However, the factor (x+1) has an even power: (x+1)^2. That means when the factor is negative, its square is positive, and when the factor is positive, its square is positive. In short, the factor (x+1)^2 causes the function to be zero at x=-1, but does not make the function change sign there.

The product of all of these factors will result in a polynomial with x^4 as the highest-degree term. That means the function is of even degree. The leading coefficient is 1, so is positive, and the function will generally have a U-shape. The left-most (odd-degree) zero will be where the function changes sign from positive to negative. The right-most (odd-degree) zero will be where the function changes sign from negative to positive. Those zeros are x=-3 and x=+4, respectively. There are no places between these where the function changes sign, so these zeros are the ends of the regions where the function is positive (>0).

3 0
2 years ago
In the diagram A, B, and C are the points on the circle. Use the diagram to prove the theorem which states that:
nevsk [136]

9514 1404 393

Explanation:

Here's one way to go at it.

Draw segments AB and CO. Define angles as follows. (The triangles with sides that are radii are all isosceles, so their base angles are congruent.)

  x = angle OAB = angle OBA

  y = angle OAC = angle OCA

  z = angle OBC = angle OCB

Consider the angles at each of the points A, B, C.

At A, we have ...

  angle CAB = x + y

At B, we have ...

  angle CBA = x + z

At C, we have ...

  angle ACB = y + z

The sum of the angles of triangle ABC is 180°, as is the sum of angles in triangle ABO. This gives ...

  x + x + ∠AOB = (x+y) +(x+z) +(y+z)

  ∠AOB = 2(y+z) = 2∠ACB

This shows ∠AOB = 2×∠C, as required.

8 0
3 years ago
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