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VMariaS [17]
3 years ago
9

What is the value of x?

Mathematics
2 answers:
Artist 52 [7]3 years ago
7 0

x^2=40^2+9^2\\x^2=1600+81\\x^2=1681\\x=\sqrt{1681}=41

ASHA 777 [7]3 years ago
3 0

To solve this you must use Pythagorean theorem:

a^{2} +b^{2} =c^{2}

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 9

b = 40

c = x

^^^Plug these numbers into the theorem

9^{2} +40^{2} =x^{2}

simplify

81 + 1600 = x^{2}

1681 = x^{2}

To remove the square from x take the square root of both sides to get you...

41 = x  

Hope this helped!

~Just a girl in love with Shawn Mendes

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Katen [24]

The value of x is B. 8.

7 0
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13. The altitude of an equilateral triangle is 6 in. long. Find the length of a side of the triangle. (Hint: what triangles are
JulijaS [17]
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6 0
3 years ago
Solve for x.<br> Help ASAP please!!!
sattari [20]

Answer:

The value of x is 4

Step-by-step explanation:

In a right triangle, if a segment is drawn from the right angle ⊥ to the hypotenuse like the given figure, then

∵ The length of one side of the right triangle = (x + 2)

∵ The length of the hypotenuse = x + 5

∴ (x + 2)² = x (x + 5)

∵ (x + 2)² = (x + 2)(x + 2)

∴ (x + 2)(x + 2) = x(x + 5)

→ Simplify the two sides

∵ (x)(x) + (x)(2) + (2)(x) + (2)(2) = (x)(x) + (x)(5)

∴ x² + 2x + 2x + 4 = x² + 5x

→ Add the like terms in the left side

∴ x² + 4x + 4 = x² + 5x

→ Subtract x² from both sides

∵ x² - x² + 4x + 4 = x² - x² + 5x

∴ 4x + 4 = 5x

→ Subtract 4x from both sides

∴ 4x - 4x + 4 = 5x - 4x

∴ 4 = x

∴ The value of x is 4

3 0
2 years ago
in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.
Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

hypotenuse^2=base^2+perpendicular^2

Use pythagoras formula for triangle PQM.

PM^2=QM^2+PQ^2

PM^2=(6)^2+(8)^2

PM^2=36+64

PM^2=100

PM=10

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

PQ^2=QR^2+PR^2

(8)^2=QR^2+x^2

64-x^2=QR^2                   .....(1)

Use pythagoras formula for triangle MQR.

MQ^2=QR^2+MR^2

(6)^2=QR^2+(10-x)^2

36=QR^2+x^2-20x+100

36-x^2+20x-100=QR^2        .... (2)

From equation (1) and (2) we get

36-x^2+20x-100=64-x^2

20x-64=64

20x=128

x=6.4

Therefore length of PR is 6.4 units and option 4 is correct.

3 0
3 years ago
6.
sweet-ann [11.9K]

Answer:

Step-by-step explanation:

<h3><em>The Answer is B, This is the answer beacuse R and S is true. There are some methonds you can do to help you solve any questions like these in the future. I hope this well help.</em></h3>
3 0
2 years ago
Read 2 more answers
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