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VMariaS [17]
3 years ago
9

What is the value of x?

Mathematics
2 answers:
Artist 52 [7]3 years ago
7 0

x^2=40^2+9^2\\x^2=1600+81\\x^2=1681\\x=\sqrt{1681}=41

ASHA 777 [7]3 years ago
3 0

To solve this you must use Pythagorean theorem:

a^{2} +b^{2} =c^{2}

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 9

b = 40

c = x

^^^Plug these numbers into the theorem

9^{2} +40^{2} =x^{2}

simplify

81 + 1600 = x^{2}

1681 = x^{2}

To remove the square from x take the square root of both sides to get you...

41 = x  

Hope this helped!

~Just a girl in love with Shawn Mendes

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Answer:

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<h3>How to determine the standard form</h3>

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