B
C
=
16.17
(
2
d
p
)
c
m
Explanation:
In triangle ABC, side
A
C
=
15
, Angles are
∠
B
=
68
0
;
∠
C
=
24
0
and
∠
A
=
180
−
(
68
+
24
)
=
88
0
We know by sine law
A
C
sin
B
=
B
C
sin
A
or
15
sin
68
=
B
C
sin
88
or
B
C
=
15
⋅
sin
88
sin
68
=
16.17
(
2
d
p
)
c
m
Step-by-step explanation:
Alternate exterior angles are the pair of angles that lie on the outer side of the two parallel lines but on either side of the transversal line. Illustration: ... Notice how the pairs of alternating exterior angles lie on opposite sides of the transversal but outside the two parallel lines.
Answer:
Two
Step-by-step explanation:
x² + 4 = 4x + 1
x² - 4x + 3 = 0
x² - 3x - x + 3 = 0
x(x - 3) - (x - 3) = 0
(x - 3)(x - 1) = 0
x = 1, 3
y = 4(1) + 1 = 5
y = 4(3) + 1 = 13
Two solutions: (1,5) (3,13)
