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horsena [70]
3 years ago
9

Zn(s) +HCl(aq) balanced

Chemistry
1 answer:
Simora [160]3 years ago
4 0

Answer:

2Zn + 2HCl = H2 + 2ZnCl

Explanation:

Zn is a metal, when metals have reaction with strong acid it will produce H2 gas and the metal's salt which is ZnCl.

Later on you just make the equation in balance.

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At the normal melting point of NaCl, 801 degrees C, its enthalpy of fusion is 28.8 kJ / mol. The density of the solid is 2.165 g
melisa1 [442]

<u>Answer:</u> The increase in pressure is 0.003 atm

<u>Explanation:</u>

To calculate the final pressure, we use the Clausius-Clayperon equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = initial pressure which is the pressure at normal boiling point = 1 atm

P_2 = final pressure = ?

\Delta H = Enthalpy change of the reaction = 28.8 kJ/mol = 28800 J/mol     (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 801^oC=[801+273]K=1074K

T_2 = final temperature = (801+1.00)^oC=802.00=[802+273]K=1075K

Putting values in above equation, we get:

\ln(\frac{P_2}{1})=\frac{28800J/mol}{8.314J/mol.K}[\frac{1}{1074}-\frac{1}{1075}]\\\\\ln P_2=3\times 10^{-3}atm\\\\P_2=e^{3\times 10^{-3}}=1.003atm

Change in pressure = P_2-P_1=1.003-1.00=0.003atm

Hence, the increase in pressure is 0.003 atm

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3 years ago
2H2 + O2 --&gt; 2H2O can be classified as what type of reaction?
Sveta_85 [38]
Combustion reaction
Key: O2
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3 years ago
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Answer:

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Answer:

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