Answer:
Do you have a screenshot of the table? I’m struggling to visualise it with the data given.
Step-by-step explanation:
Answer:
2/3 x ![\sqrt[4]{y^2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7By%5E2%7D)
Step-by-step explanation:
( 16 x^11 y^8 / 81 x^7 y^6) ^ ( 1/4)
Simplify the expression inside the parentheses
Rewriting the constant
16/81 = 2^4 / 3^4 = (2/3) ^4
Next the x terms
x^11 / x^7
We know that a^b / a^x = a^ ( b-c)
x^ (11-7) = x^4
And finally the y term
y^8/ y^6 = y^( 8-6) = y^2
( (2/3) ^4 x^4 y^2) ^ ( 1/4)
We know that (ab) ^ c = a^ c * b^c
(2/3) ^4 ^ 1/4 ( x^4 ^ 1/4 ( y^2) ^ ( 1/4)
We know that a^ b^ c = a^ ( b*c)
(2/3) ^4 ^ 1/4 ( x^4 ^ 1/4 ( y^2) ^ ( 1/4)
( 2/3) ^ ( 4*1/4) * x^ ( 4*1/4) * y ^ ( 2 ^ 1/4)
2/3 * x * y ^ 2/4
2/3x y ^ 2/4
2/3 x
Scince the sum of a triangle is 180° just subtracts 180 from 67 which should be 113
Answer:
a. the probability that any one of the computers will require repair on a given day is constant
Step-by-step explanation:
The following properties must be true in order for a distribution to be binomial:
- A fixed number of trials (125 computers)
- Each trial is independent of the others (one computer requiring repair does not interfere with the likelihood of another requiring repair).
There are only two outcomes (requires repair or do not require repair)
The probability of each outcome remains constant from trial to trial (All computers have the same likelihood of requiring repair, 0.15).
Therefore, the alternative that better fits those properties is alternative a. the probability that any one of the computers will require repair on a given day is constant
