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3 years ago

What is the value of the y-coordinate of point A

Mathematics

1 answer:

kap26 [50]3 years ago

6 0

Answer: $-\dfrac{1}{2}$

<u>Step-by-step explanation:</u>

The coordinate at -30° <em>(-30° = 330°)</em> = $\bigg(\dfrac{\sqrt3}{2},-\dfrac{1}{2}\bigg)\\$

the x-value is $\dfrac{\sqrt3}{2}$

the y-value is $-\dfrac{1}{2}\\$

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3 X + 9 is greater than 4 x minus 16

+ 25 is greater than x

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3 years ago

Is 81 divisible by 3?

AlexFokin [52]

Yes 81 is divisible by 3
the answer is 27
because 81 divided by 3 = 27

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3 years ago

Read 2 more answers

Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If

vesna_86 [32]

Answer:

<h2>The probability is 58 %.</h2>

Step-by-step explanation:

This problem belong to a normal distribution probability.

Mean = 63.6

Standard Deviation = 2.5.

We have to find the probability of a height greater than 63.0.

Due to the normal probability, we need to find the Z score first:

$Z=\frac{x-u}{o}$ ; where x is the height, u is the mean, and o is the standard deviation.

$Z=\frac{63-63.6}{2.5} \\Z= -0.24$

Once we have our Z score, we find the probability with the z-table (attached). So, for a z score of -0.24 we have a probability of 0.42.

But, the problem is asking for height greater than 63.0, this mean that we have to subtract 0.42 from 1, giving as result 0.58, which means a 58% of probability,

6 0

3 years ago

Housing Price.The file calledsaratoga.JMPcontains data on 1728 houses in Saratoga, NewYork in the year 2006. The dataset include

Juliette [100K]

Answer:

iii. priceof a house in Saratoga, N.Y.

Step-by-step explanation:

In this question, we take a sample from house prices of 1728 houses in Saratoga, New York.

Since only houses from Saratoga are part of the sample, the response variable will be related only to Saratoga.

In this question:

Sample to find house prices in Saratoga, which is the variable of interest. The correct answer is given by option iii.

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3 years ago

Find the length of the shorter diagonal of a rhombus if:

Fudgin [204]

a) Area of rhombus = ½ * (diagonal1)*(diagonal 2)

Let diagonal (D2 )= longer diagonal = 15 and diagonal (D1) = shorter diagonal

90 = ½ (D1)*15

90 = 7.5 D1

Now divide both side by 7.5

90/7.5 = d1

D1= 12 units.

b) Area of rhombus = ½ * (diagonal1)*(diagonal 2)

Let the ratio be $x$

Diagonal 1= $2x$

Diagonal 2= $3x$

147 = ½ * $(2x)*(3x)$

Multiply both side by 2

294 = $(2x)*(3x)$

294 = 6 $x^2$

Divide both side by 6

294/6 = 6 $x^2$ /6

49 = $x^2$

$x$ = 7 unit

8 0

3 years ago