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4 years ago

Tan(x+pi/2)= negative cot x

1 answer:

6 0

I'm only going to alter the left hand side. The right side will stay the same the entire time

I'll use the identity tan(x) = sin(x)/cos(x) and cot(x) = cos(x)/sin(x)
I'll also use sin(x+y) = sin(x)cos(y)+cos(x)sin(y) and cos(x+y) = cos(x)cos(y)-sin(x)sin(y)

So with that in mind, this is how the steps would look:

tan(x+pi/2) = -cot x
sin(x+pi/2)/cos(x+pi/2) = -cot x
(sin(x)cos(pi/2)+cos(x)sin(pi/2))/(cos(x)cos(pi/2)-sin(x)sin(pi/2)) = -cot x
(sin(x)*0+cos(x)*1)/(cos(x)*0-sin(x)*1) = -cot x
(0+cos(x))/(-sin(x)-0) = -cot x
(cos(x))/(-sin(x)) = -cot x
-cot x = -cot x

Identity is confirmed

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AfilCa [17]

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3 years ago

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Sara receives a 9% commission on every car she sells. The car dealership paid $20,000 for a car from an auction. The next day th

Paladinen [302]

Hey there! Your answer to this problem is 2160..

Explanantion:

Since every car Sara sells, she gets 9% of the commission, this means that at the last few step, we would have to give 9% of the total cost to Sara.

If 100% is 20,000, then 50% would be 10,000. But we have to find the cost of 20%. So what we would actually be doing is multiplying 20 with 0.01. 20x0.01 is 0.2 or 0.20.

Then you add the 4,000 to the 20,000 because it states, “the next day, they sold the car 20% more than they paid. This means that you’ll have to add it. 20,000 plus 4000 would be 24,000. So 24,000 would be the cost of the car they sold.

However they didn’t wanna know the cost of the car, they wanted to know how much Sara would get. So you would have to take 9% of the cost of the cost which would be 2,160.

Final result: $2,160

4 0

3 years ago

Connecticut families were asked how much they spent weekly on groceries. Using the following data, construct and interpret a 95%

Amanda [17]

Answer:

The 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

Step-by-step explanation:

The data for the amount of money spent weekly on groceries is as follows:

S = {210, 23, 350, 112, 27, 175, 275, 50, 95, 450}

n = 10

Compute the sample mean and sample standard deviation:

$\bar x =\frac{1}{n}\cdot\sum X=\frac{ 1767 }{ 10 }= 176.7$

$s= \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} } = \sqrt{ \frac{ 188448.1 }{ 10 - 1} } \approx 144.702$

It is assumed that the data come from a normal distribution.

Since the population standard deviation is not known, use a t confidence interval.

The critical value of t for 95% confidence level and degrees of freedom = n - 1 = 10 - 1 = 9 is:

$t_{\alpha/2, (n-1)}=t_{0.05/2, (10-1)}=t_{0.025, 9}=2.262$

*Use a t-table.

Compute the 95% confidence interval for the population mean amount spent on groceries by Connecticut families as follows:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}$

$=176.7\pm 2.262\cdot\ \frac{144.702}{\sqrt{10}}\\\\=176.7\pm 103.5064\\\\=(73.1936, 280.2064)\\\\\approx (73.20, 280.21)$

Thus, the 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

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3 years ago

Bad White [126]

Answer:

Which Number Is x, You Didnt Specify

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3 years ago

What is the u known decimal equivalent for 5/100.

dexar [7]

I think that answer would be .05

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3 years ago

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