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3 years ago

I will appreciate if you answer this problem,thanks

Mathematics

1 answer:

aliya0001 [1]3 years ago

3 0

Answer:

None

Step-by-step explanation:

By graphing out the both line segments through graphing software, segments AB and CD have no intersections on the co-ordinate plane.

I've attached a screenshot of what i graphed out.

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I need help again different question tho

VladimirAG [237]

Answer:

44u-36

Step-by-step explanation:

Apply the distributive property.

−6(−7u)−6⋅6+2u

Multiply −7 by −6.

42u−6⋅6+2u

Multiply −6 by 6.

42u−36+2u

Add 42u and 2u.

44u-36

8 0

2 years ago

Find the value of x so that the function has the givin value n(x)=2x+7, n(x)=17

Sunny_sXe [5.5K]

Answer: x=5

Step-by-step explanation:

Substitute 17 for n(x)

17=2x+7

Subtract 7 from both sides

10=2x

Divide each side by 2 to get the x by itself

x=5

6 0

3 years ago

Janeel has a 10-inch by 12-inch photograph. She wants to scan the photograph, then reduce the result

Vaselesa [24]

Complete Question:

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

Correct Answer:

A) $(10-x)(12-x)=15$

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

Step-by-step explanation:

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

$length=10-x\\breadth=12-x$

According to question , Area of new image is :

⇒ $Area = \frac{1}{8}Length(breadth)$

⇒ $Area = \frac{1}{8}(10)(12)$

⇒ $Area = 15$

So the equation will be :

⇒ $(10-x)(12-x)=15$

b. Find the dimensions of the reduced image

Let's solve : $(10-x)(12-x)=15$

⇒ $120-10x-12x+x^2=15$

⇒ $120-22x+x^2=15$

⇒ $x^2-22x+105=0$

By Quadratic formula :

⇒ $x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $x = \frac{22 \pm8 }{2}$

⇒ $x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}$

⇒ $x = 15 , x =7$

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ $x =7$

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

5 0

3 years ago

Which of the following best describes the angles shown?

rodikova [14]

Vertical angles, because the definition of vertical lines is each of the pairs of opposite angles made by two intersecting lines.

3 0

3 years ago

Help? im confused plss! Find the area of the regular polygon with the given radius or apothem

Snezhnost [94]

Answer:

50 cm²

Step-by-step explanation:

Given that the regular polygon is a square, there are multiple ways you can jump directly to the answer. Perhaps the simplest is to use the formula for the area of a rhombus:

A = 1/2(d1)(d2)

where d1 and d2 are the lengths of the diagonals. Here, we see that half the diagonal is 5 cm, so the area is ...

A = (1/2)(10 cm)(10 cm) = 50 cm² . . . . area of the polygon

Alternate solution

If you want to use the radius and the number of sides in a formula, you can consider the area of each triangle formed by radii and a side. That triangle has area ...

A = 1/2r²sin(α)

where r is the radius and α is the central angle. For an n-sided polygon, the area is the sum of n of these triangles, and the central angle is 360°/n. Then the polygon area is ...

A = n/2·r²·sin(360°/n)

For n = 4 and r = 5 cm, the area is ...

A = (4/2)(5 cm)²(sin(360°/4)) = 2(5 cm)²(1) = 50 cm² . . . . area of square

_____

Additional comment

The formula is somewhat different if you start with the length of the apothem. One way to find the area is using the above formula and the relation between the radius and apothem:

r = a·sec(180°/n)

Another formula uses the apothem directly:

A = n·a²·tan(180°/n)

8 0

2 years ago