The work done to push the box is equal to the product between the force and the distance through which the force is applied:
In our problem, the force is F=1.4 N and the distance covered is d=150 m, so the work done by pushing the box is
Answer:
The answer to your question is: 10.48 km/s
Explanation:
Data
h = 5.6 x 10⁶ m
g = 9.8 m/s²
Formula
vf = 
Substitution
vf = 
vf = 
vf = 10476.64 m/s
convert to km/s
vf = 10476.64/1000
vf = 10.48 km/s
Answer:
100 m/s
Explanation:
Mass the mass of Bond's boat is m₁. His enemy's boat is twice the mass of Bond's i.e. m₂ = 2 m₁
Initial speed of Bond's boat is 0 as it won't start and remains stationary in the water. The initial speed of enemy's boat is 50 m/s. After the collision, enemy boat is completely stationary. Let v₁ is speed of bond's boat.
It is the concept of the conservation of momentum. It remains conserved. So,
Putting all the values, we get :
So, Bond's boat is moving with a speed of 100 m/s after the collision.
"Valence" electrons or the free electrons
<u>Explanation:</u>
Electrical conductivity can be defined as the property of the substance to conduct electricity, heat etc through it. This conductivity is caused due to the migration of particles which are electrically charged within the atomic lattice of the substance.
The outermost electrons or the electrons in valence shell are the main cause behind the conductivity property exhibited by any substance. Higher the number of electrons in outer shell, higher the conductivity.
Since these electrons are in the outermost shell, they can move easily. Under an impact of applied heat, charge these electrons migrate through the atomic lattice and thus conducts electricity, heat as the case may be.
Answer:
<h2>a) 496N</h2><h2>b) 50.56kg</h2><h2>c) 1.90m/s²</h2>
Explanation:
According to newton's secomd law, ∑F = ma
∑F is the summation of the force acting on the body
m is the mass of the body
a is the acceleration
Given the normal force when the elevator starts N1 = 592N
Normal force after the elevator stopped N2 = 400N
When the elevator starts, its moves upward, the sum of force ∑F = Normal (N)force on the elevator - weight of the person( Fg)
When moving up;
N1 - Fg = ma
N1 = ma + Fg ...(1)
Stopping motion of the elevator occurs after the elevator has accelerates down. The sum of forces in this case will give;
N2 - Fg = -ma
N2 = -ma+Fg ...(2)
Adding equation 1 and 2 we will have;
N1+N2 = 2Fg
592N + 400N = 2Fg
992N 2Fg
Fg = 992/2
Fg = 496N
The weight of the person is 496N
<em>\b) To get the person mass, we will use the relationship Fg = mg</em>
g = 9.81m/s
496 = 9.81m
mass m = 496/9.81
mass = 50.56kg
c) To get the magnitude of acceleration of the elevator, we will subtract equation 1 from 2 to have;
N1-N2 = 2ma
592-400 = 2(50.56)a
192 = 101.12a
a = 192/101.12
a = 1.90m/s²
