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Diano4ka-milaya [45]
3 years ago
9

What happens when light strikes a translucent object?

Physics
2 answers:
Ne4ueva [31]3 years ago
6 0

Answer:

D

Explanation:

Its the answer on my usatestprep

sammy [17]3 years ago
3 0

Answer:

D)   Some of the light passes through, and some of the light is absorbed or scattered by the object.

Explanation:

When light strikes translucent materials, only some of the light passes through them. The light does not pass directly through the materials. ... When light strikes an opaque object none of it passes through. Most of the light is either reflected by the object or absorbed and converted to heat.

(I googled it) ☺

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The number of electorn is morn than proton in nuclie. why?​
ziro4ka [17]

protons and neutrons have a mass of 1, while electrons have almost no mass.

8 0
2 years ago
Assuming the atmospheric pressure is 1 atm at sea level, determine the atmospheric pressure at Badwater (in Death Valley, Califo
tiny-mole [99]

Answer:

Atmospheric pressure at Badwater is 1.01022 atm

Explanation:

Data given:

1 atmospheric pressure (Pi) = 1.01 * 10^{5} Pa

Elevation (h) = 86m

gravity (g) = 9.8 m/s2

Density of air P = 1.225 kg/m3

Therefore pressure at bad water Pb = Pi + Pgh

Pb = (1.01 * 10^{5}) + (1.225 * 9.8 * 86)

Pb = (1.01 * 10^{5}) + 1032.43 = 102032 Pa

hence:

Pb = 102032 /1.01 * 10^{5} = 1.01022 atm

4 0
3 years ago
Which of these is the most effective way for Leanna to cool down after an intense bike ride
Sonja [21]
I am pretty sure the answer would be too stretch
6 0
3 years ago
Explain why a real image must be produced in a camera and how the object and the lens are positioned to produce a real image whi
PilotLPTM [1.2K]
This is best explained through the use of an optics diagram, this is a little too complicated to explain in a short answer, and as I can't draw an appropriate diagram in this answer, I will point you to this excellent resource which explains what you have asked very well!

Go onto the BBC website (you should have access to it even if you aren't in the UK) and paste this after the BBC url,

/bitesize/intermediate2/physics/waves_and_optics/image_formation_from_lens/revision/1/
5 0
3 years ago
An arrow of mass 415 g is shot at a target with a speed of 68.5m/s. The target, which has a mass of 3.3 kg, is moving toward the
Murrr4er [49]

The velocity of the target and arrow after collision is 6.67m/s

<u>Explanation:</u>

Given:

Mass of arrow, mₐ = 415g

Speed of arrow, vₐ = 68.5m/s

Mass of the target, mₓ = 3.3kg = 3300g

speed of the target, vₓ = -1.1m/s (Because the target moves in opposite direction

Velocity of the target and arrow after collision, vₙ = ?

Applying the conservation of momentum,

mₐvₐ + mₓvₓ = (mₐ+mₓ) vₙ

415 X 68.5 + 3300 X -1.1 = (415+3300) X vₙ

28427.5 - 3630 = 3715 X vₙ

24797.5 = 3715 X vₙ

vₙ = 6.67m/s

Therefore, the velocity of the target and arrow after collision is 6.67m/s

4 0
3 years ago
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