An aluminum wire having a cross-sectional area equal to 3.90 10-6 m2 carries a current of 6.00 A. The density of aluminum is 2.7
1 answer:
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The strength of the gravitational field is given by:
where
G is the gravitational constant
M is the Earth's mass
r is the distance measured from the centre of the planet.
In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
And now we can use the previous equation to calculate the field strength at that altitude:
And we can see this value is a bit less than the gravitational strength at the surface, which is
.
where
G is the gravitational constant
M is the Earth's mass
r is the distance measured from the centre of the planet.
In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
And now we can use the previous equation to calculate the field strength at that altitude:
And we can see this value is a bit less than the gravitational strength at the surface, which is
Answer:
The approximate number of decays this represent is
Explanation:
From the question we are told that
The amount of Radiation received by an average american is
The source of the radiation is
Generally
Therefore
Also
Therefore
An Average american weighs 88.7 kg
The total energy received is mathematically evaluated as
Cross-multiplying and making x the subject
Therefore the total energy deposited is
The approximate number of decays this represent is mathematically evaluated as
N =
Where n is the approximate number of decay
Substituting values