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bija089 [108]
3 years ago
14

Explain how using renewable and recyclable materials can benefit the environment.

Biology
2 answers:
Ierofanga [76]3 years ago
8 0
Instead of burning coal to power our country we could use solar panels. As long as we have the sun we will have "free" energy.

Instead of continuing to mine for metals, we could recycle metals and then less greenhouse gases would be released into Earth's atmosphere.
Nuetrik [128]3 years ago
7 0

The renewable and recyclable material helps to keep the environment clean and green.

Renewable resources can be defined as the the resources that can be renewed again once used. These resources does not causes pollution no matter how much you use it.

Recyclable materials are the material that can be remolded to use again. Both of the above materials does not pollute the environment and keeps it green and clean.

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1.)<span>a. antibodies
 2.)</span><span>b. its mechanism is well understood</span>
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How do I know that diagram of amoeba cell division is Asexual reproduction in an amoeba
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Answer:

Amoeba reproduces asexually through binary fission. In this process, an individual divides itself into two daughter cells. These are genetically identical to each other.

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Both ancestral birds and ancestral mammals shared a common ancestor that was a terrestrial vertebrate. today, penguins (which ar
arlik [135]

Answer:

Homologous; analogous

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A new kind of tulip is produced that develops only purple or pink flowers. Assume that flower color is controlled by a single-ge
Sophie [7]

Answer:

a. purple allele (C) = 0.609, pink allele (c) = 0.391

b. purple homozygotes = 371, pink homozygotes = 153, heterozygotes = 476

Explanation:

Given -

Purple flowers - 847

Pink flowers - 153

The frequency of recessive genotype i.e

q^ 2 = \frac{153}{1000} \\q^ 2 = 0.153\\

Frequency of recessive allele i.e q is equal to

q = \sqrt{0.153} \\q = 0.391

As per hardy Weinberg's first equilibrium equation -

p + q = 1\\p = 1-q\\p = 1-0.391\\p = 0.609

Frequency of purple homozygous species

= p^2\\= 0.609^2\\= 0.371

Number of purple homozygous species = 0.371 * 1000= 371

Number of pink homozygous species = 0.153 * 1000= 153

Heterozygous species is equal to

(1-0.371-0.153)* 1000\\= 0.476 * 1000\\= 476

5 0
3 years ago
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What structures connect digestive glands to the digestive track?
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Mouth, pharynx, esophagus
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