1. (6, -329°) (-6, 211°) (-6, -149°)
2. (5, -5π/3) (-5, 4π/3) (-5,-2π/3)
Notice: (+,+),(+,-),(-,+),(-,-).
If we consider angles beyond 360° or 2π, many other names for these points can be determined.
The polar coordinate can be written as (r, θ) = (r, θ + 2nπ) or (r, θ) = [ - r, θ + (2n + 1)π ], where n is any integer
Answer:
Answer: ???
Step-by-step explanation:
By applying tangent rule in the given right triangle AOB,
tan(30°) =
By applying tangent rule in the given right triangle BOC,
tan(60°) =
OC = BO(√3)
OA + OC = AC
2√3(BO) = 60
BO = 10√3
OC = (10√3)(√3)
OC = 30
By applying tangent rule in right triangle DOC,
OD = OC(√3)
OD = 30√3
Since, BD = BO + OD
BD = 10√3 + 30√3
BD = 40√3
≈ 69.3
Question 1
probability of a red marble in the first draw = 1/10
probability of a orange marble in the second draw = 4/9
probability of getting red in first and orange in second (without replacement) = 1/10 * 4/9 = 2/45,
Question 2
6 outcomes
1/6
-2/4
rise over run down 2, -2 run we ran 4 +4