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3 years ago

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Charles predicts he will get 97 points on the test at the end of the week. If Charles gets 87 points on the test, what is Charle

s' percent error? Round your answer to the nearest tenth of a percent.

1 answer:

xz_007 [3.2K]3 years ago

6 0

97 - 87 = 10
10/87 = <span>0.11494252873
</span>0.11494252873 * 100 = <span>11.4942528736
</span>Round to nearest tenth of a percent = <span>11.5%</span>

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What is the inverse of f(x)=(x+6)2 for x≥–6 where function g is the inverse of function f? g(x)=x√−6, x≥0 g(x)=x−6−−−−√, x≥6 g(x

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Answer:

$g(x)=\sqrt{x}-6$ , x>=0

Step-by-step explanation:

$f(x)=(x+6)^2$

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A simple random sample of size n equals 200 individuals who are currently employed is asked if they work at home at least once p

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Answer: 99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

Step-by-step explanation:

<u>step 1:-</u>

Given sample size n=200

of the 200 employed individuals surveyed 41 responded that they did work at home at least once per week

Population proportion of employed individuals who work at home at least once per week P = $\frac{x}{n} =\frac{41}{200} =0.205$

Q=1-P= 1-0.205 = 0.705

<u>step 2:-</u>

Now $\sqrt{\frac{P Q}{n} } =\sqrt{\frac{(0.205)(0.705)}{200} }$

=0.0015

<u>step 3:-</u>

<u>Confidence intervals</u>

<u>using formula</u>

$(P - Z_∝} \sqrt{\frac{P Q}{n},} (P + Z_∝} \sqrt{\frac{P Q}{n},$

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<u>conclusion:</u>-

99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

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