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Leviafan [203]
3 years ago
10

Write a program that reads an unspecified number of integers, determines how many positive and negative values have been read, a

nd computes the total and average of the input values (not counting zeros). Your program ends with the input 0. Display the average as a floating-point number. Sample Run 1 Enter an integer, the input ends if it is 0: 1 2 -1 3 0 The number of positives is 3 The number of negatives is 1 The total is 5.0 The average is 1.25 Sample Run 2 Enter an integer, the input ends if it is 0: 0 No numbers are entered except 0 Sample Run 3 Enter an integer, the input ends if it is 0: 2 3 4 5 0 The number of positives is 4 The number of negatives is 0 The total is 14 The average is 3.5 Sample Run 4 Enter an integer, the input ends if it is 0: -4 3 2 -1 0 The number of positives is 2 The number of negatives is 2 The total is 0 The average is 0.0
Computers and Technology
1 answer:
GarryVolchara [31]3 years ago
5 0

Answer:

<em>C++</em>

////////////////////////////////////////////////////////////////////////////////////////////////////////

#include <iostream>

#include <vector>

using namespace std;

int main() {

  vector<int> v;

   int n = 1;

   while (n != 0) {

       cout<<"Enter an integer, the input ends if it is 0: ";

       cin>>n;

       v.push_back(n);

   }

   cout<<endl;

   ///////////////////////////////////////////////////////////

   int sum = 0;

   int num_positives = 0, num_negatives = 0;

   for (int i=0; i<v.size()-1; i++) {

       if (v[i] > 0)

           ++num_positives;

       else

           ++num_negatives;

           

       sum = sum + v[i];

   }

   //////////////////////////////////////////////////////////

   cout<<"The number of positives is "<<num_positives<<endl;

   cout<<"The number of negatives is "<<num_negatives<<endl;

   cout<<"The total is "<<sum<<endl;

   cout<<"The average is "<<(float)sum/(v.size()-1);

   ///////////////////////////////////////////////////////////

   return 0;

}

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