Question

Write a program that reads an unspecified number of integers, determines how many positive and negative values have been read, and computes the total and average of the input values (not counting zeros). Your program ends with the input 0. Display the average as a floating-point number. Sample Run 1 Enter an integer, the input ends if it is 0: 1 2 -1 3 0 The number of positives is 3 The number of negatives is 1 The total is 5.0 The average is 1.25 Sample Run 2 Enter an integer, the input ends if it is 0: 0 No numbers are entered except 0 Sample Run 3 Enter an integer, the input ends if it is 0: 2 3 4 5 0 The number of positives is 4 The number of negatives is 0 The total is 14 The average is 3.5 Sample Run 4 Enter an integer, the input ends if it is 0: -4 3 2 -1 0 The number of positives is 2 The number of negatives is 2 The total is 0 The average is 0.0

Answer 1

Answer:

C++

////////////////////////////////////////////////////////////////////////////////////////////////////////

#include <iostream>

#include <vector>

using namespace std;

int main() {

  vector<int> v;

   int n = 1;

   while (n != 0) {

       cout<<"Enter an integer, the input ends if it is 0: ";

       cin>>n;

       v.push_back(n);

   }

   cout<<endl;

   ///////////////////////////////////////////////////////////

   int sum = 0;

   int num_positives = 0, num_negatives = 0;

   for (int i=0; i<v.size()-1; i++) {

       if (v[i] > 0)

           ++num_positives;

       else

           ++num_negatives;

           

       sum = sum + v[i];

   }

   //////////////////////////////////////////////////////////

   cout<<"The number of positives is "<<num_positives<<endl;

   cout<<"The number of negatives is "<<num_negatives<<endl;

   cout<<"The total is "<<sum<<endl;

   cout<<"The average is "<<(float)sum/(v.size()-1);

   ///////////////////////////////////////////////////////////

   return 0;

}