For this case we have that by definition of properties of powers and roots, it is fulfilled that:
\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}
n
a
m
=a
n
m
So:
\sqrt [4] {9 ^ {\frac {1} {2} x}} = 9 ^ {\frac {\frac {1} {2}} {4} x} = 9 ^ {\frac {1} {8} x}
4
9
2
1
x
=9
4
2
1
x
=9
8
1
x
So, we have to:
\sqrt [4] {9 ^ {\frac {1} {2} x}} = 9 ^ {\frac {1} {8} x}
4
9
2
1
x
=9
8
1
x
Answer:
9 ^ {\frac {1} {8} x}9
8
1
x
Option B
pa heart mo na at i reat mo ko at i follow
The restrictions are what the denominator can not be. The denominator cannot be zero. So if the denominator has x+1 in it. If you put -1 in place of x. You would get zero. -1 is a restriction
That is system of equation.
Answer:
This isn’t really a valid equation, so I’m guessing you forgot to type something.
Step-by-step explanation:
Answer:
$149.09
Step-by-step explanation:
56.75-14.10=42.65
42.65+41.50=84.15
84.15-11.03=73.12
73.12-7.25=65.87
65.87+83.22=149.09
