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RideAnS [48]
4 years ago
9

Please answer will give brainliest

Mathematics
1 answer:
Marysya12 [62]4 years ago
6 0

Answer: Your answer would be D (:

Step-by-step explanation: Just pretend that each cube is worth 7 so you would multiply 7x7x7x7x7x7= 42(: Hope This Helped!!!!(:

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Trees are planted 6 metres apart on both sides of road 48 metres long.how many trees were planted​
Varvara68 [4.7K]

Answer:

16 on both sides

Step-by-step explanation:

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What is the written form of the decimal number .954
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Nine hundred fifty-four thousandths.
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A new company, Games 2 U, is selling unlimited video game rentals online for up to 5 devices. They are offering two different pr
Basile [38]

The expression of the two plans( EZ Plan and Big Time Gamer Plan) are as follows:

y = 0.10x

y = 0.05x + 100

<h3>How to represent expression?</h3>

The company is offering two different pricing options.

The EZ Plan is $0.10 per minute.

The Big Time Gamer Plan is $0.05 per minute plus a $100 monthly charge.

Therefore, the EZ pricing plan can be express as follows:

y = 0.10x

Therefore, the Big Time Gamer Plan can be express as follows:

y = 0.05x + 100

where

x = minutes playing games in a month

y = The total cost of the plans

Let's set them equal to each other.

0.10x  = 0.05x + 100

Learn more about expression here: brainly.com/question/17207480

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8 0
2 years ago
What are the coordinates of point A?<br> A (–4, 3)<br> B (3, –4)<br> C (–3, –4)<br> D(–4, –3)
fomenos

Answer:

The coordinates of point a according to graph would be (-4,-3).

x = -4 , y = -3

hope it helps!

6 0
3 years ago
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The braking distance Dv (in meters) for a certain car moving at velocity v (in meters/second) is given by =Dvv234.
MaRussiya [10]

Answer:

S(t)=\frac{9t^2}{34}

Step-by-step explanation:

We are given that

Th braking distance for a certain car moving at velocity v(in m/s) is given by

D(v)=\frac{v^2}{34}

The velocity of car B(t) t seconds after starting =B(t)=3t

We have to find the value for braking distance S(t) after t seconds.

To find the formula for braking distance we will substitute the value of velocity B(t) in place of v in D(v)

Substitute the value of velocity then we get

Then, we get

The formula for the braking distance S(t) after t seconds=\frac{(3t)^2}{34}

The formula for the braking distance S(t) after t seconds=\frac{9t^2}{34}

8 0
3 years ago
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