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3 years ago

What is the measure (in radians) of central angle theta in the circle below? enter an exact expression.

Mathematics

1 answer:

Llana [10]3 years ago

6 0

Answer:

Measure of central angle is 3.665 radians

Step-by-step explanation:

In this question, we are trying to get the value of the central angle.

As we can see, the radius of the circle is 12cm while the length of the major arc is 14 pi cm.

Mathematically the length of an arc is calculated as follows;

Length of arc = theta/360 * 2 * pi * r

Plugging the values we have from the question;

14 pi = theta/360 * 2 * pi * 12

divide both sides by 2pi

7 = theta/360 * 12

360 * 7 = 12 theta

theta = (360 * 7)/12

theta = 210

Since 1 degree = pi/180 radian

it means 210 degrees = 210 * pi/180 = 3.665 radians

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Answer:

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The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

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Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

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Therefore, the length between points AB is

length AB = $\sqrt{(-4 - (-2))^2+(-1-3)^2}$

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Length BC = $\sqrt{(-4)^2+1^2} = \sqrt{17}$ = 4.123 units

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Length DA = $\sqrt{(8)^2+(-2)^2} = \sqrt{68}$ = 8.246 units

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If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A = $\sqrt{(7)^2+(0)^2} = \sqrt{49}$ =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

$S_{\bigtriangleup}$ = $(\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|$

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A(-4,-1)

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$S_{{\bigtriangleup}ABC}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

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D'(3, -1)

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