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2 years ago

I WILL GIVE CROWN FOR ANSWER

Mathematics

2 answers:

Angelina_Jolie [31]2 years ago

7 0

The answer is 49 fl ounces

GenaCL600 [577]2 years ago

5 0

49 because 3 1/4 pints is equal 52 oz (you multiple the 3 1/4 by 16 because that is the conversation) and then there’s 3 oz left so you subtract 52-3 and you get 49 oz

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^ this week, The sparkling water was 4 for $5 , the regular was $1.69

S_A_V [24]

This week you paid $1.25 each because they were on sale for four for $5.

4 0

3 years ago

natka813 [3]

Answer:

x= -8 , y = 5

x= 25/4 , y = 1/4

Step-by-step explanation:

substitute first eqn into the second eqn:

(7 - 3y)^2 -y^2 = 39

49 - 42y + 9y^2 - y^2 = 39

8y^2 - 42y +10 =0

4y^2 - 21y + 5 = 0

(4y-1) (y-5) = 0

y= 1/4 , 5

when y=1/4

x = 7- 3/4

=25/4

when y= 5

x = 7- 15

= -8

5 0

3 years ago

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F(x)=(x+4)(x-2)(x+4)(x+4)<br><br> What is the multiple zero? Multiplicity is?

kari74 [83]

$f(x)=(x+4)(x-2)(x+4)(x+4)\\f(x)=(x+4)^3(x-2)=0\\(x+4)^3=0~|~(x-2)=0\\(x+4)(x+4)(x+4)=0~|~x=2\\x=-4,2$

The multiple zero is x = -4.

The multiplicity is 2 because there are two values of x.

8 0

2 years ago

Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7

rosijanka [135]

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$

Notice that $x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1)$ . Decompose the integrand into partial fractions:

$\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}$
$=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}$

Integrating term-by-term, you get

$\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx$
$=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C$

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3 years ago

Which one of the following is NOT equal to the others?

irina1246 [14]

Answer:

.03

Step-by-step explanation:

.03 would be 3% where all the others are 30% hope this helped!

5 0

3 years ago

Read 2 more answers