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3 years ago

Evaluate the expression when x=-2 and y=3. -y+8x 0 Х 5 ?

Mathematics

1 answer:

FromTheMoon [43]3 years ago

8 0

Answer:

Step-by-step explanation:

First here is the problem

-y + 8x

nwo that u have the problem substitute the variables with numbers...see example

-3 + (8) (-2)

Then Order of operations do the multiplication...so see example below

-3 + (16) Its negative -16 because a positive and negative when multiplied is negative

Now -3 + 16 = 13

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Brian drove 120 miles at a speed of 60 mph. He drove the same distance back home at an average speed of 40 mph. Brian adds the s

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4 years ago

The first five terms of an arithmetic sequence are shown below: 20, 17, 14, 11, 8, . . . let n represent the term number and f(n

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For starters, find the common change in the terms, in this case each goes down by 3. This lets you know you're gonna have a -3n in your equation as each term decreases by 3. Your equation should be in f(n)=c+rn form, with r being change in f(n), or -3 in this case. This gives you f(n)=c-3n. Now, solve for c, add 3n to both sides to get f(n)+3n=c. Plug in your n of 1 and f(n) of 20 to get c=20+3(1)=23. Plug in your c to your f(n) formula to get f(n)=23-3n as your f(n) function.

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3 years ago

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Another way to write 4/5

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Need help fast please

dalvyx [7]

Answer:

13. The slope for a line that is perpendicular to the line y=4x+8 is -1/4

14. The slope for a line that is perpendicular to the line x=-6 is 0

15. The equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin is y = - (1/2) x

16. The equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10) is y=3x-10

Step-by-step explanation:

13. What is the slope for a line that is perpendicular to the line y=4x+8?

y=mx+b

Comparing with the form slope-intercept, the slope of the given line is the coefficient of x, then the slope of the given line is 4.

A line perpendicular to y=4x+8 must have a slope opposite and inverse, then:

Slope of the perpendicular = - 1/4

14. What is the slope for a line that is perpendicular to the line x=-6?

The line x=-6 is a vertical line. A line perpendicular to the line x=-6 must be a horizontal line (Angle=0°), then:

Slope of the perpendicular = tan Angle = tan 0° = 0

15. Write the equation for a line that is perpendicular to the line 8x-4y=12 and passes through the origin.

8x-4y=12

Isolating y: Subtracting 8x both sides of the equation:

8x-4y-8x=12-8x

-4y=-8x+12

Dividing all the terms by -4:

-4y/(-4)= -8x/(-4)+12/(-4)

y=2x-3

The slope of the given line is 2

The slope of the perpendicular is m=-1/2 (opposite and inverse to the slope of the given line)

The perpendicular passes through the origin:

P1=(0,0)=(x1,y1)→x1=0, y1=0

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-0=(-1/2)(x-0)

y=(-1/2)x

16. Write an equation for a line that is perpendicular to the line y=-(1/3)x and passes through the point (0,-10).

The slope of the given line is -(1/3)

The slope of the perpendicular is m=3/1→m=3 (opposite and inverse to the slope of the given line)

The perpendicular passes through the point:

P1=(0,-10)=(x1,y1)→x1=0, y1=-10

Using the equation point - slope:

y-y1=m(x-x1)

Replacing the known values:

y-(-10)=3(x-0)

y+10=3x

Isolating y: Subtracting 10 both sides of the equation:

y+10-10=3x-10

y=3x-10

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4 years ago