parallel lines have the same slope
y = 4x-5 the slope is 4
slope intercept form
y= mx+b
the slope is 4 and the y intercept is 3
y = 4x +3
Answer:
Q13. y = sin(2x – π/2); y = - 2cos2x
Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1
Step-by-step explanation:
Question 13
(A) Sine function
y = a sin[b(x - h)] + k
y = a sin(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Phase shift = π/2.
2h =π/2
h = π/4
The equation is
y = sin[2(x – π/4)} or
y = sin(2x – π/2)
B. Cosine function
y = a cos[b(x - h)] + k
y = a cos(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Reflected across x-axis, y ⟶ -y
The equation is y = - 2cos2x
Question 14
(A) Sine function
(1) Amp = 2; a = 2
(2) Shifted down 1; k = -1
(3) Per = π; b = 2
(4) Phase shift = 0; h = 0
The equation is y = 2sin2x -1
(B) Cosine function
a = 2, b = -1; b = 2
Phase shift = π/2; h = π/4
The equation is
y = -2cos[2(x – π/4)] – 1 or
y = -2cos(2x – π/2) - 1
Answer:
c = 3 c = -1/2
Step-by-step explanation:
(4c-5)^2= 49
Take the square root of each side
sqrt((4c-5)^2)= ±qrt(49)
4c-5 = ±7
Separate into two equations
4c-5 = 7 4c-5 = -7
Add 5 to each side
4c-5+5 = 7+5 4c-5+5 =-7+5
4c =12 4c = -2
Divide by 4
4c/4 = 12/4 4c/4 = -2/4
c = 3 c = -1/2
Answer:
(a,b)------>(-1,-7)let
now
m(x-a)=(y-b)
2(x+1)=(y+7)(where m=slope
2x+2=y+7
2x-y=7-2
2x-y=5 is a required equation.
A im getting outta my version
