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zhuklara [117]
3 years ago
15

What technique do API developers most commonly use to limit access to an API to authorised individuals and applications?

Computers and Technology
1 answer:
miss Akunina [59]3 years ago
3 0

Answer:

API keys

Explanation:

API (Application Programming Interface) is a computing interface that defines the interaction between multiple software intermediaries.

API key is a specific identifier use authenticate the developer user and call programs for the API.

The API keys often serve as a specific identifier and a secret token for authentication, and usually have a set of access rights to the API associated with it.

These are commonly used to authenticate a project with an API instead of a human user. Different platforms can execute and use API keys in different ways.

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3 years ago
What is ana absolute adress
AleksAgata [21]

Answer:

The term <u>absolute</u> distinguishes it from a relative address, which indicates a location specifying a distance from another location. <u>Absolute addresses</u> are also called real addresses and machine addresses.

Explanation:

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The sequence of instructions performed to execute one program instruction
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Answer:

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Explanation:

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3 years ago
The _____ search algorithm searches a list for a given item, starting with the first element and continues to compare the item w
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Answer:

Sequential

Explanation:

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7 0
3 years ago
Given two ArrayLists of sorted strings (alphabetically ascending), write down a method to merge these sorted strings’ ArrayLists
Elena-2011 [213]

Answer:

see explaination

Explanation:

import java.util.ArrayList;

import java.util.Arrays;

public class Merge {

public static ArrayList<String> mergeList(ArrayList<String> lst1, ArrayList<String> lst2) {

ArrayList<String> result = new ArrayList<String>();

int i = 0, j = 0;

while (i < lst1.size() || j < lst2.size()) {

if (i < lst1.size() && (j >= lst2.size() || lst1.get(i).compareTo(lst2.get(j)) < 0)) {

result.add(lst1.get(i++));

} else {

result.add(lst2.get(j++));

}

}

return result;

}

public static void main(String[] args) {

ArrayList<String> lst1 = new ArrayList<>(Arrays.asList("Austin", "Dallas", "San Fransisco"));

ArrayList<String> lst2 = new ArrayList<>(Arrays.asList("Boston", "Chicago", "Denver", "Seattle"));

System.out.println(mergeList(lst1, lst2));

}

}

8 0
3 years ago
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