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3 years ago

Let f(x) = 7x - 13. Find f-1(x).

1 answer:

4 0

$f(x)=7x-13 \\ \\ y=7x-13 \ \ \ |+13 \\
y+13=7x \ \ \ |\div 7 \\
x=\frac{1}{7}y+\frac{13}{7} \\ \\
\boxed{f^{-1}(x)=\frac{1}{7}x+\frac{13}{7}}$

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2 years ago

Simplify (3x − 8) + (2x + 5) − (4x − 8).<br> A) x − 11 <br> B) x + 5 <br> C) x + 21 <br> D) 9x + 5

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2 years ago

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In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

$\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}$

$\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}$

$\text{The weight of average pumpkin}=5\text{ kg}$

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

$1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

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3 years ago

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How would you write y=2/3x+1/3 in point slope form??

gladu [14]

Answer:

y - 1 = 2/3(x - 1).

Step-by-step explanation:

Point slope form is y - y1 = m(x - x1) where m = the slope and (x1, y1) is a point on the line.

y = 2/3x + 1/3 which gives the slope m = 2/3.

We can now find a point on the line by putting x = 1 say then find y:

y = 2/3(1) + 1/3 = 2/3 + 1/3 = 1 so the point is (1, 1).

(x1, y1) = (1, 1)

So the answer is ;

y - 1 = 2/3(x - 1).

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3 years ago