<u>Given: </u>
- Breadth of canvas is 22 inches.
- Length of canvas is 38 inches.
<u>To Find:</u>
- If kendra covered 30% of the canvas by painting red rose, what will be the area of canvas covered by red rose?
<u>Solution: </u>
To find the area of red rose, first we have to find the area of canvas.
★ Area of Rectangle = Length × Breadth
➝ 22 × 38
➝ 836 in²
So, Area of canvas is 836 inches².
★ Area of red rose:-
➝ 30% of 836 in²
➝ 0.30 of 836
➝ 250.8
Hence, Area covered by the red rose is <u>2</u><u>5</u><u>0</u><u>.</u><u>8</u>
<h2> ____________________</h2><h3><u>Additional</u><u> </u><u>Information:</u><u> </u></h3>
★ Triangle => ½bh
★ Rectangle => Length × Breadth
★ Circle => πr²
★ Square => Side × Side
★ Parallelogram => Base × Height
★ Sphere => 4πr²
They are all equal to 6w+11x-9y
Answer:
the anser is a
Step-by-step explanation:
We write the equation in terms of dy/dx,
<span>y'(x)=sqrt (2y(x)+18)</span>
dy/dx = sqrt(2y + 18)
dy/dx = sqrt(2) ( sqrt(y + 9))
Separating the variables in the equation, we will have:
<span>1/sqrt(y + 9) dy= sqrt(2) dx </span>
Integrating both sides, we will obtain
<span>2sqrt(y+9) = x(sqrt(2)) + c </span>
<span>where c is a constant and can be determined by using the boundary condition given </span>
<span>y(5)=9 : x = 5, y = 9
</span><span>sqrt(9+9) = 5/sqrt(2) + C </span>
<span>C = sqrt(18) - 5/sqrt(2) = sqrt(2) / 2</span>
Substituting to the original equation,
sqrt(y+9) = x/sqrt(2) + sqrt(2) / 2
<span>sqrt(y+9) = (2x + 2) / 2sqrt(2)
</span>
Squaring both sides, we will obtain,
<span>y + 9 = ((2x+2)^2) / 8</span>
y = ((2x+2)^2) / 8 - 9
3.8 if u use long division u will get 3.8 hope that helps. Good luck too
