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3 years ago

8

Which transformation of Figure A results in Figure A'?

1 answer:

spayn [35]3 years ago

8 0

From the figure the coordinates of A are:
(-8,-4), (-6,-3), (-4,-5)
The coordinates of A' are: (-4,-6),(6,-5),(8,-7)
subtracting 2 corresponding points we get:
[(4--8),(-6--4)]
=(12,-2)
this means that the image has been translated 12 units to the right and 2 units down.
Answer:

<span>a translation 12 units right and 2 units down.</span>

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ANSWER.

The correct answer is Option A

EXPLANATION.

The real number

$\sqrt{35}=5.916079783$

to 9 decimal places.

You can see that the decimals are not repeating, neither will they terminate.

Therefore the real number $\sqrt{35}$ is irrational because, the decimal does not terminate or repeat

Also note that,

$\sqrt{35}=\sqrt{5} \times \sqrt{7}$ .

That is,

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3 years ago

1. Which of the following questions has a constant of

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Answer:

In B) y = x/7 , the constant of proportionality is 7.

Step-by-step explanation:

Two quantities X and Y are said to be in proportion if and only if

X = kY or, $\frac{X}{Y} = k$ ,

where k = Proportionality Constant.

Here, 7 is the constant of proportionality. Then,

A . y = 14x

here, $\frac{y}{x} = 14$ ≠ 7

B . y = x/7

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Lou has an account with $10,000 which pays 6% interest compounded annually. If to that account, Lou deposits $5,000 at the begin

katovenus [111]

Answer:

Option d. $22154 is the right answer.

Step-by-step explanation:

To solve this question we will use the formula $A=P(1+\frac{r}{n})^{nt}$

In this formula A = amount after time t

P = principal amount

r = rate of interest

n = number of times interest gets compounded in a year

t = time

Now Lou has principal amount on the starting of first year = 10000+5000 = $15000

So for one year $A=15000(1+\frac{\frac{6}{100}}{1})^{1\times1}$

$= 15000(1+.06)^{1}$

$= 15000(1.06)$ = $15900

After one year Lou added $5000 in this amount and we have to calculate the final amount he got

Now principal amount becomes $15900 + $ 5000 = $20900

Then putting the values again in the formula

$A=20900(1+\frac{\frac{6}{100}}{1})^{1\times1}$

$= 20900(1+.06)^{1}$

$= 20900(1.06)=22154$

So the final amount will be $22154.

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