3 years ago

Please help me with this question , which panda was heavier when they were born image shown

Mathematics

2 answers:

kumpel [21]3 years ago

7 0

Answer:

Kappa

Step-by-step explanation:

Mochi weighed 1 pound when he was born, and Kappa weighed 2 pounds when he was born. Therefore, Kappa is the answer.

kondor19780726 [428]3 years ago

7 0

Answer: kappa

Step-by-step explanation: the chart goes

0, 2, 4, 6, 8...etc it goes by two’s.

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Given h()<br> - 4x - 4, solve for a when h(x)<br> -8.

Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

this is a function

if h(x) is -8 you would plug it in for x:

-4(-8) -4 a negative × a negative is a positive

32- 4= 28

7 0

3 years ago

Read 2 more answers

The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27

Naddik [55]

ANSWER
$3\pi sq.\: in.$

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

$R:r=3:1$

We can rewrite it as fractions to get,

$\frac{R}{r} = \frac{3}{1}$

We make R the subject to get,

$R = 3r$

The area of the bigger circle can be found using the formula,

$Area=\pi {r}^{2}$

This implies that,

$Area=\pi ({3r})^{2}$

$Area=9\pi {r}^{2}$

But it was given in the question that, the area of the bigger circle is 27π.

$27\pi=9\pi {r}^{2}$

We divide through by 9π to get,

$3 = {r}^{2}$

This means that,
$r = \sqrt{3}$

The area of the smaller circle is therefore

$= \pi {( \sqrt{3}) }^{2}$

$= 3\pi$