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3 years ago

A) Two sides of a triangle are 22 inches and 17 inches.

Mathematics

2 answers:

Triss [41]3 years ago

6 0

The answer would be either isosceles or scalene triangle. hope that helped

coldgirl [10]3 years ago

4 0

If your looking for the area, the answer is 187

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If it takes 500ml to fill up a liter of soda, how many ml will it take to fill up<br>5 liters?

Pie

Answer:

2,500

Step-by-step explanation:

500 * 5 = 2,500

8 0

3 years ago

Read 2 more answers

A telemarketing company calls telephone numbers chosen at random. It finds that 30% of calls are not completed (the party does n

cupoosta [38]

Answer:

21%

Step-by-step explanation:

Actually there are three levels of process here.

If 100 calls are made only 70 calls are completed (since 30%not completed)

Out of these 70 completed we find that 40% i.e. 28 calls to a woman and 30% i.e. 21 go to a man.

28 females and 21 males

Out of 28 females 45% buy something = $0.45*28=12.6$

Out of 21 males 40% buy something = $0.4*21=8.4$

Total percent of calls result in a sale = $12.6+8.4=21$

So 21% of calls result in a sale

7 0

3 years ago

The sum of two numbers is 27 and their product is 50. Find the numbers.?<br><br>

san4es73 [151]

Answer:

a + b = 27

=> a = 27 - b

ab = 50

So, (27 - b) x b = 50

27b - b^2 = 50

b^2 - 27b + 50 = 0

Solving, b = 25, 2

Hence,

Case 1: b = 25, a = 2

Case 2, b = 2, a = 25

5 0

2 years ago

Read 2 more answers

PLEASE HELP PLEASE HELP

Burka [1]

Answer:

The answer should be 15, since each week the number goes up by 15.

5 0

2 years ago

Read 2 more answers

There are two vendors at the fair sleeping snow cones for the same price. If the containers are completely filled and then level

aliya0001 [1]

Answer:

$d = 787.81cm^3$

Step-by-step explanation:

Given

See attachment for the containers

Required

The difference in the amount of snow cone they hold

The amount they hold is determined by calculating the volume of the containers.

The traditional snow cone has the following dimension

Shape: Cone

$r=4cm$ --- radius

$h = 13cm$ --- height

The volume is calculated as:

$Volume = \frac{1}{3} \pi r^2h$

So, we have:

$V_1 = \frac{1}{3} \pi * 4^2 * 13$

$V_1 = \frac{208}{3} \pi$

The snow cone in a cup has the following dimension

Shape: Cylinder

$r=8cm$ --- radius

$h = 5cm$ --- height

The volume is calculated as:

$Volume = \pi r^2h$

So, we have:

$V_2 = \pi *8^2 * 5$

$V_2 = \pi *320$

$V_2 = 320\pi$

The difference (d) in the amount they hold is:

$d = V_2 - V_1$

$d = 320\pi - \frac{208\pi}{3}$

Take LCM

$d = \frac{3*320\pi -208\pi}{3}$

$d = \frac{960\pi -208\pi}{3}$

$d = \frac{752\pi}{3}$

Take $\pi = 22/7$

$d = \frac{752}{3} * \frac{22}{7}$

$d = \frac{752 * 22}{3*7}$

$d = \frac{16544}{21}$

$d = 787.81cm^3$

4 0

3 years ago