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2 years ago

Please help me, I will give brainliest.

Mathematics

1 answer:

WITCHER [35]2 years ago

7 0

Answer:

Sorry there is no solution

Step-by-step explanation:

There is not way to find the area with out other information.

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Please help me if possible

ss7ja [257]

Answer: 8 cm

Step-by-step explanation:

To do this, we just need to divide 256 by each of the numbers.

First let’s divide 256 by 8

256/8=32

Then divide 32 by 4

32/4 = 8.

Therefore your answer is 8 cm.

3 0

3 years ago

What is -3 (6x -4) + 2 (2x -4) = - 50

padilas [110]

Answer:

$\frac{27}{7}$

5 0

2 years ago

Read 2 more answers

The exact circumference of a circle is 34π meters. What is the approximate area of the circle? Use 3.14 for π. Round to the near

LiRa [457]

Answer:

A = 907.46 $m^{2}$

Step-by-step explanation:

C = πd

34π = πd

d = 34

r = 17

A = $\pi r^{2}$ = 3.14( $17^{2}$ ) = 3.14(289) = 907.46 $m^{2}$

3 0

3 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers

Which of the following describes a linear function

liq [111]

Answer:

Step-by-step explanation:

Linear function means that the y values depend upon the x values and any other numbers that are being added to it.

3 0

3 years ago