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faust18 [17]
3 years ago
15

Two-fifiths as a fraction

Mathematics
2 answers:
Fantom [35]3 years ago
6 0

Answer:

2/5

Step-by-step explanation:

two is the numerator

5 is the denominator

you have 2 "1/5"s

Nataly_w [17]3 years ago
3 0

Answer:

The answer is 2/5

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Johson has 4 points. If a line connects two points, how many lines can he draw? <br> 1,4,6 or 12
Maslowich
The answer is 6
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7 0
3 years ago
What is th GCF of 21 and 18
ZanzabumX [31]

Answer:

The answer is 3.

Explanation:

Factors of 18:

1, 2, 3, 6, 9, 18.

Factors of 21:

1, 3, 7.

The highest number that both sets contain is 3, so the GCF will be 3.


5 0
3 years ago
Read 2 more answers
If x^2+y^2=1, what is the largest possible value of |x|+|y|?
Marianna [84]

If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).

Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).

If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.

• Case 1: suppose <em>x</em> < 0. Then

<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = -1/√2   →   <em>y</em> = ±1/√2

• Case 2: suppose <em>x</em> ≥ 0. Then

<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = 1/√2   →   <em>y</em> = ±1/√2

In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.

6 0
2 years ago
A club swimming pool is 21 ft wide and 33 ft long. the club members want an exposed aggregate border in a strip of uniform width
vovangra [49]
First compute the perimeter of the pool:
(21+33)*2=108 foot. 
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232/108=2.1

The trip can be 2.1 ft in wide. 
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3 years ago
Please help .!!!!!!!!!!!!!!!!!!!
Mrrafil [7]

Answer:

The answer is C

Step-by-step explanation:


8 0
3 years ago
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