Please help me out with this!!
1 answer:
Answer:
see attached
Step-by-step explanation:
<h3>1.</h3>Solid dots go at all the end points except the one at (3, 6), which gets an open dot signifying the function is not defined for that point.
For the first portion of the graph, the square root function is shifted left one unit and scaled vertically by a factor of 3.
The second portion of the graph is a line with a slope of -1. It would have a y-intercept of 5 if it were defined there. It has an x-intercept of 5.
<h3>2.</h3>The y-intercept is found by setting x=0 and solving for y.
... y = log(2·0+1) -1 = log(1) -1 = 0 -1 = -1
The x-intercept is found by setting y=0 and solving for x.
... 0 = log(2x +1) -1
... 1 = log(2x +1) . . . add 1
... 10 = 2x +1 . . . . . . take the antilog
... x = (10 -1)/2 = 4.5 . . . . . subtract 1, divide by the x coefficient
The intercepts are (0, -1) and (4.5, 0).
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Given:
A line contains the points R(-1, 8), S(1, 4) and T(6, y).
To find:
The value of y.
Solution:
Three points are collinear if:
A line contains the points R(-1, 8), S(1, 4) and T(6, y). It means, these points are collinear.
Subtract 12 from both sides.
Divide both sides by 2.
Therefore, the value of y is -6.