1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
RideAnS [48]
3 years ago
9

Which answer choice best explains why uranium-238 can be used in power plants to generate electricity?

Chemistry
1 answer:
Lemur [1.5K]3 years ago
8 0
Uranium is a fissionable material to which if you split it, it makes a lot of heat which is used in reactors for massive energy production.
You might be interested in
(3.5 × 1016)(2.2 × 1010) = A × 10B
saveliy_v [14]
1016)(2.2<span> × </span>1010<span>) = A × </span>10B<span> A= B= Chemistry.</span>
6 0
3 years ago
Read 2 more answers
The cells of plant and animals lack nuclei
Masteriza [31]
That is not true 
They both have nuclei or we would not be living now
6 0
3 years ago
A 10.0 mL sample of HNO3 was exactly neutralized by 13.5 mL of 1.0 M KOH. What is the molarity of the HNO3? Use the titrations f
Kruka [31]

Answer: Thus molarity of HNO_3 is 1.35 M

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=?M\\V_1=10.0mL\\n_2=1\\M_2=1.0M\\V_2=13.5mL

Putting values in above equation, we get:

1\times M_1\times 10.0=1\times 1.0\times 13.5\\\\M_1=1.35M

Thus molarity of HNO_3 is 1.35 M

7 0
3 years ago
I don’t get how to do it
san4es73 [151]

Answer:

Use the x method, cross over each charge.

Explanation:

K^{+1} and Br^{-1} the +1 and -1 cancel each other out, so it will be KBr

3 0
3 years ago
The normal boiling point of methanol is 64.7 ∘ C and the molar enthalpy of vaporization is 71.8kJ/mol . The value of ΔS when 1.3
guapka [62]

Answer:

286 J/K

Explanation:

The molar Gibbs free energy for the vaporization (ΔGvap) is:

ΔGvap = ΔHvap - T.ΔSvap

where,

ΔHvap: molar enthalpy of vaporization

T: absolute temperature

ΔSvap: molar entropy of the vaporization

When T = Tb = 64.7 °C = 337.9 K, the reaction is at equilibrium and ΔGvap = 0.

ΔHvap - Tb . ΔSvap = 0

ΔSvap = ΔHvap/Tb = (71.8 × 10³ J/K.mol)/ 337.9 K = 212 J/K.mol

When 1.35 mol of methanol vaporizes, the change in the entropy is:

1.35mol.\frac{212J}{K.mol} =286 J/K

7 0
3 years ago
Other questions:
  • Which of the following compounds is most likely to dissolve in water?
    6·2 answers
  • Suppose a compound is involved in three different reactions denoted R1, R2, and R3. Tripling the concentration of this reactant
    9·1 answer
  • Which tool can be used to measure the volume of a liquid to one decimal place?
    14·2 answers
  • What kind of force pushes particles in the atomic nucleus apart?
    15·1 answer
  • Explain what is wrong with the following structure.
    14·2 answers
  • What plant is known to live for just a few hours?​
    14·1 answer
  • In the Energy and Specific Heat lab, how should the water bath be stabilized over the heat source? Select one:
    9·2 answers
  • If 225 cal of heat is added to 15.0 g of 2-propanol at room temperature, 25ºC, the alcohol will reach a final temperature of ___
    13·1 answer
  • What is the density of krypton gas (MM = 83.8 g/mol) at 3.00<br> atm and 100. °C?<br> g/L
    8·1 answer
  • Based on the following chemical equation how many hydrogen atoms are present in the products side?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!