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HACTEHA [7]
3 years ago
9

In the Energy and Specific Heat lab, how should the water bath be stabilized over the heat source? Select one:

Chemistry
2 answers:
Reika [66]3 years ago
5 0

Answer:

c

Explanation:

butalik [34]3 years ago
3 0

Answer:

C

Explanation:

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Sediment spreads horizontality and it goes from youngest on top to oldest on bottom. When sediment deposits in water, it also sp
Ad libitum [116K]
My answer will be C. Law of Original lateral continuity. :)
7 0
3 years ago
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Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water. Suppose 0.802 g of methane i
Kipish [7]

Answer:

1.07g

Explanation:

Step 1:

We will begin by writing the balanced equation for the reaction. This is given below:

CH4 + 2O2 —> CO2 + 2H2O

Step 2:

Determination of the masses of CH4 and O2 that reacted and the mass of H2O produced from the balanced equation. This is illustrated below:

Molar Mass of CH4 = 12 + (4x1) = 12 + 4 = 16g/mol

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 2 x 32 = 64g

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Mass of H2O from the balanced equation = 2 x 18 = 36g

Summary:

From the balanced equation above,

16g of CH4 reacted with 64g of O2 to produce 36g of H2O.

Step 3:

Determination of the limiting reactant.

We need to know which of the reactant is limiting the reaction in order to obtain the maximum mass of water.

This is illustrated below:

From the balanced equation above,

16g of CH4 reacted with 64g of O2.

Therefore, 0.802g of CH4 will react with = (0.802 x 64)/16 = 3.21g of O2.

From the above calculations, a higher mass of O2 is needed to react with 0.802g of CH4. Therefore, O2 is the limiting reactant.

Step 4:

Determination of the mass of H2O produced from the reaction.

To obtain the maximum mass of H2O produced, the limiting reactant will be used because it will generate the maximum yield of the product.

From the balanced equation above,

64g of O2 produce 36g of H2O.

Therefore, 1.9g of O2 will produce = (1.9 x 36)/64 = 1.07g of H2O.

The maximum mass of water (H2O) produced by the reaction is 1.07g

8 0
3 years ago
7.62 x 10^23 molecules of CO2 are contained in a tire. How large is the tire (in liters)?​
konstantin123 [22]

Answer: 7.62e+23

Explanation:

3 0
3 years ago
the Temperature of a sample of an ideal gas in a sealed 5.0 l container is raised from 27 oC to 77oC. If the initial pressure of
matrenka [14]
Answer:
              The pressure increases to 3.5 atm.

Solution:
                According to Gay-Lussac's Law, " At constant volume and mass the pressure of gas is directly proportional to the applied temperature".

For initial and final states of a gas the equation is,

                                           P₁ / T₁  =  P₂ / T₂
Solving for P₂,
                                           P₂  =  P₁ T₂ / T₁    ----- (1)

Data Given;
                   P₁  =  3 atm

                   T₁  =  27 °C + 273  =  300 K
 
                   T₂  =  77 °C + 273  =  350 K

Putting values in eq. 1,

                                           P₂  =  (3 atm × 350 K) ÷ 300 K

                                           P₂  =  3.5 atm
7 0
3 years ago
Use the equation editor or "Insert Chemistry - WIRIS editor" to write the balanced molecular chemical equation for the reaction
Mariana [72]

Answer:

The balanced molecular equation  for the reaction :

Cu(NO_3)_2(aq)+K_2CO_3(aq)\rightarrow CuCO_3(s)+2KNO_3(aq)

Explanation:

The reaction between copper(II) nitrate  and potassium carbonate gives solid precipitate of copper(II) carbonate and aqueous solution of potassium nitrate.

Cu(NO_3)_2(aq)+K_2CO_3(aq)\rightarrow CuCO_3(s)+2KNO_3(aq)

According to reaction, 1 mole of copper(II) nitrate reacts with 1 mole of potassium carbonate to give 1 mole of copper(II) carbonate and 2 moles of potassium nitrate,

8 0
3 years ago
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